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Yeah i will dude or dudet ask away
4y-8>10
Add 8
4y-8+8>10+8
4y>18
Now divide both sides by 4
4y/4 > 18/4
y>9/2
Now let's see if it will be true
Replace y by its value
4(9/2)-8>10
36/2 -8 > 10
18-8 > 10
10 > 10
That's false because 10 can not smaller than 10
so it should be = instead
Answer : False
I hope that's help:)
1) -3
2) 6
3) 4
4) 2
5) 5
6) 5
7) 7
8) -3
9) 9
10) 6
11) -5
12) 0
Here are your answers may I please have the brainliest
Answer:segment YZ ≈ 19.4 inangle X ≈ 85.3°angle Z ≈ 26.7°Explanation:1) Given two side lenghts and one angle you can use sine law:

2) Using the sides with length 43 in and 40in, and the corresponding opposite angles, Z and 68°, that leads to:

From which you can clear sinZ and get:
sinZ = 43 × sin(68) / 40 = 0.9967
⇒ Z = arcsine(0.9967) ≈ 85.36°
3) The third angle can be determined using 85.36° + 68° + X = 180°
⇒ X = 180° - 85.36° - 68° = 26.64°.
4) Finally, you can apply the law of sine to obtain the last missing length:

From which: x = 40 × sin(26.64°) / sin(68°) = 19.34 in
The answer, then is:
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°