1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
statuscvo [17]
2 years ago
7

Because energy is conserved, we can calculate kinetic or potential energy at all times if we know one or the other at different

times. For example, if a car on a roller coaster has 1000J of potential energy when its parked at the top of the ride, and later it only has 100J of potential energy, we know that it must have 1000-100=900 joules of Potential energy at that later time.
If the car has 250J of potential energy at some point in the ride, how much kinetic energy does it have?

a
750
b
100
c
850
d
7
e
200
Mathematics
1 answer:
trasher [3.6K]2 years ago
4 0

Answer:

ohh what's the topic

Step-by-step explanation:

its so hard hahhahahahah

You might be interested in
What’s the answer to this?
antiseptic1488 [7]

Answer:

17

Step-by-step explanation:

4 0
3 years ago
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

t=-\text{ln}(\frac{1}{3})\cdot 20

t=-(\text{ln}(1)-\text{ln}(3))\cdot 20

t=-(0-\text{ln}(3))\cdot 20

t=20\text{ln}(3)

Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

6 0
3 years ago
You roll a 6-sided die. What is P(6)? Write your answer as a fraction or whole number.
Dimas [21]

Answer:

1/6

Step-by-step explanation:

There are six sides, so if u want to roll a six, that will be 1/6

3 0
3 years ago
How is the graph of g(x) = (x-3)^3 related to the graph of f(x) = x^3
Ket [755]

Answer:

Hewo frends

I believe in you you can do this u can make do this just never give up or give in

my job is to motivate ppl

UwU

3 0
3 years ago
Simplify <br> 3sin 0+ 2sin 0- 4sin0+ 5sin0<br> step by step
Ymorist [56]

Answer:

0

Step-by-step explanation:

3x0+2x0-4x0+5x0

0

5 0
3 years ago
Read 2 more answers
Other questions:
  • Cassie ran up 8 flights of stairs.write an integer to represent the situation
    14·1 answer
  • 3/2n-7/2n = - 8/5<br>What does n equal?
    12·1 answer
  • On a number line, show all points whose coordinates satisfy the following inequalities: |x−20|&lt;5
    12·2 answers
  • Solve the given system of equations.
    9·1 answer
  • F(x)=11x -x +2 find the potential rational zeros
    8·1 answer
  • What is the solution of VX-4+5=2?​
    11·2 answers
  • 0.4(2-q=0.2(q+7) hurry please
    10·1 answer
  • What compound inequality describes the graph shown below?
    5·1 answer
  • Triangle JKL is dilated with the origin as the center of dilation to create J’K’L’.
    13·2 answers
  • If you pay $43 for a set of Pokémon cards online that were listed for $40 what is the tax percent you were charged
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!