Answer:
x° = 37°
Step-by-step explanation:
* Lets revise some facts of a circle
- The secant is a line intersect the circle in two points
- If two secants intersect each other in a point outside the circle,
then the measure of the angle between them is half the difference
of the measures of their intercepted arcs
* Now lets solve the problem
- There is a circle
- Two secants of this circle intersect each other in a point outside
the circle
∴ The measure of the angle between them = 1/2 the difference of the
measures of their intercepted arcs
∵ The measure of the angle between them is x°
∵ The measures of their intercepted arcs are 26° and 100°
- Use the rule above to find x
∴ x° = 1/2 [ measure of the large arc - measure of small arc]
∵ The measure of the large arc is 100°
∵ The measure of the small arc is 26°
∴ x° = 1/2 [100 - 26] = 1/2 [74] = 37°
∴ x° = 37°
Answer:
5 meters
Step-by-step explanation:
Based on the situation, it forms into a right triangle. So we will apply the Pythagorean Theorem here. The ladder acts as the hypotenuse while the height from the ground to the window serves as our side "a". We are tasked to solve for "b". Side "b" is the distance from foot of side a to the tip of side c which is the hypotenuse (ladder). We will derive the formula below to solve for b.
c = √( a² + b² )
c² = a² + b²
b² = c² - a²
b = √ ( c² - a² )
b = √ ( 13² - 12² )
b = 5 meters
Correct me if I'm wrong. I hope it helps.
I need another number for this problem to answer
Answer:
<h2>
The width, x, of this parallelogram is 16 cm.</h2>
Step-by-step explanation:
In #14, the area of the parallelogram is 528 cm².
This area is also the value of the formula A = L·W:
A = 528 cm² = (33 cm)·W
To determine the width, W, of this parallelogram, we perform the following division:
W = (528 cm²) / (33 cm) = 16 cm
The width, x, of this parallelogram is 16 cm.
Answer:
603.2 meters
Step-by-step explanation:
circle - the outside of the walk in this case. This circle has a
diameter of 22 + 8 m, therefore a radius of 15m. The inner circle
has a diameter of 22m - as given - a radius of 11m.
You subtract the area of the inner circle from that of the larger circle.
