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3 years ago

What is the data path width for a dimm that supports ecc?

Mathematics

1 answer:

vitfil [10]3 years ago

6 0

Normally, the data path width for DIMMs is 64 bits but for the DIMMs that support ECC, the data path is 72 bits.

To add, error checking uses the extra 8 bits. ECC memory is more reliable than non-ECC memory but it costs more than a non-ECC memory. Comprising the DIMMS are a series of dynamic random-access memory integrated circuits. Mounted on a printed circuit board, these modules are designed for use in personal computers, workstations and servers.

The most common kinds of internal data corruption are detected and corrected by a type of computer data storage called error-correcting code memory.

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Fill in the missing numbers to find two equivalent fractions 4/5 please help !!

konstantin123 [22]

First fill in the blank box is 2 second is 8 third is 80

7 0

3 years ago

Find a formula for dy/dx if sin x + cos y + sec(xy) = 251

Lena [83]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{-cos(x) - ysec(xy)tan(xy)}{-sin(y) + xsec(xy)tan(xy)}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Distributive Property

<u>Algebra I</u>

Factoring

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Trig Differentiation

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Implicit Differentiation

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

sin(x) + cos(y) + sec(xy) = 251

<u>Step 2: Differentiate</u>

[Implicit Differentiation] Trig Differentiation [Chain Rule]: $\displaystyle cos(x) - sin(y)\frac{dy}{dx} + sec(xy)tan(xy) \cdot (y + x\frac{dy}{dx}) = 0$
[Subtraction Property of Equality] Isolate $\displaystyle \frac{dy}{dx}$ terms: $\displaystyle -sin(y)\frac{dy}{dx} + sec(xy)tan(xy) \cdot (y + x\frac{dy}{dx}) = -cos(x)$
[Distributive Property] Distribute sec(xy)tan(xy): $\displaystyle -sin(y)\frac{dy}{dx} + ysec(xy)tan(xy) + xsec(xy)tan(xy)\frac{dy}{dx} = -cos(x)$
[Subtraction Property of Equality] Isolate $\displaystyle \frac{dy}{dx}$ terms: $\displaystyle -sin(y)\frac{dy}{dx} + xsec(xy)tan(xy)\frac{dy}{dx} = -cos(x) - ysec(xy)tan(xy)$
Factor out $\displaystyle \frac{dy}{dx}$ : $\displaystyle \frac{dy}{dx}[-sin(y) + xsec(xy)tan(xy)] = -cos(x) - ysec(xy)tan(xy)$
[Division Property of Equality] Isolate $\displaystyle \frac{dy}{dx}$ : $\displaystyle \frac{dy}{dx} = \frac{-cos(x) - ysec(xy)tan(xy)}{-sin(y) + xsec(xy)tan(xy)}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

5 0

3 years ago

Jacob ate 21 Chips Ahoy cookies in 1 hour and Bryant ate 25 Chips Ahoy cookies in the same time. At this rate, how many whole co

Alja [10]

Answer:

55 cookies in 80 mins

Step-by-step explanation:

1 hour has 60 mins

so 25/60=0.417

0.417/3=0.139

0.139x4=0.556

so he can eat 55 cookies in 80 mins

3 0

4 years ago

Someone please help me with math

trasher [3.6K]

Hi I use symbolab.com to help me solve algebraic equations it also fives you steps it really helped me to understand algebra.

5 0

4 years ago

Use the box plot to answer the questions. What is the range of Charles’s scores? What is the median of Charles’s scores? What is

vekshin1

Box-plot describes 5 important data of the observations. We get following values for range, median and IQR as:

The range of Charles' scores is 20
The median of Charles' scores is 90
The IQR of Charles' scores is 8

<h3>How does a boxplot shows the data points?</h3>

A box plot has 5 data description.

The leftmost whisker shows the minimum value in the data.
The rightmost whisker shows the maximum value in the data.
The leftmost line in the box shows the first quartile.
The middle line shows the median, also called second quartile.
The last line of the box shows the third quartile.

<h3>How to find the interquartile range?</h3>

IQR(inter quartile range) is the dfference between third and first quartile. (Its the horizontal length of the box)

<h3>What is the range of a data set?</h3>

Range = Maximum value of the data set - Minimum value of the dataset

The missing box plot is attached below for the given problem.

From the given data, we see that, the left and right whiskers are on 80 and 100 respectively.

The left and right limit of the box are on 85 and 93 respectively.

The middle line lies on 90.

Thus, we get:

Minimum score = left whisker = 80
Maximum score = right whisker = 100
First quartile = left limit of box = 85
Third quartile = right limit of box = 93
Second quartile = median = middle line's position in the box = 90

Thus, we get:

Range of Charles' score = Max - min value = 100 = 80 = 20
Median of Charles' score = 90
IQR = third quartile - first quartile = 93 - 85 = 8

Learn more about box plot here:

brainly.com/question/1523909

8 0

2 years ago