Answer:
1/2?
Step-by-step explanation:
Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
<h3>
How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Step-by-step explanation: To solve this absolute value inequality,
our goal is to get the absolute value by itself on one side of the inequality.
So start by adding 2 to both sides and we have 4|x + 5| ≤ 12.
Now divide both sides by 3 and we have |x + 5| ≤ 3.
Now the the absolute value is isolated, we can split this up.
The first inequality will look exactly like the one
we have right now except for the absolute value.
For the second one, we flip the sign and change the 3 to a negative.
So we have x + 5 ≤ 3 or x + 5 ≥ -3.
Solving each inequality from here, we have x ≤ -2 or x ≥ -8.


Step-by-step explanation:
if 'c' is meant to be another 'x' the answer is
(3, 1)
x = 3,y = 1
<h2>
Explanation:</h2><h2>
</h2>
Let's solve this problem graphically. Here we have the following equation:

So we can rewrite this as:

So the solution to the equation is the x-value at which the functions f and g intersect. In other words:

Using graphing calculator, we get that this value occurs at:
