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Degger [83]
3 years ago
7

Amira is solving the equation x2 – 6x = 1. Which value must be added to both sides of the equation to make the left side a perfe

ct-square trinomial?
Mathematics
1 answer:
Lorico [155]3 years ago
7 0

Answer:

its 9

Step-by-step explanation:

I have  gotten it correct on ED

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Samantha can run one mile in 8 minutes. At this rate how long will it take her to run in 5 miles
Serhud [2]
It would take Samantha 40 minutes to run 5 miles!!!
4 0
3 years ago
Read 2 more answers
Write the Prime factors that 24 and 36 have in common By showing them multiplied together
lakkis [162]

The prime factors that the numbers 24 and 36 have in common are found out to be; 2 × 2 × 3

<h3>How to get prime factors? </h3>

A prime factor of a number is simply factor of that number that is a prime number. This means that any of the prime numbers that can be multiplied to give the original number.

Now, we have;

Prime factors of 36; 2 × 2 × 3 × 3

Prime factors of 24; 2 × 2 × 2 × 3

The prime factors that they have in common will be; 2 × 2 × 3

Read more about Prime factors at; brainly.com/question/1081523

#SPJ1

5 0
2 years ago
there are n counters in a bag. 4 of the counters are red and the rest are blue. Ross takes a counter from the bag at random and
Ainat [17]

Answer: n = 10.

Step-by-step explanation:

In the bag, we have n counters.

4 of the counters are red.

the rest are blue, then we have:

(n - 4) blue counters.

Now, the probability that Ross takes a blue counter from the bag is equal to the quotient between the number of blue counters (n - 4) and the total number of counters, n

Then the probability is:

p1 = (n - 4)/n

Now he draws another, and it must be blue again, then we can calculate the probability in the same way as above, but he already take a blue counter, so the number of blue counters is (n - 5) and the total number of counters is (n - 1)

The probability of this event is:

p2 = (n - 5)/(n - 1)

The joint probability (the probability that Ross takes two blue counters) is equal to the product of the individual probabilities, and we know that this is equal to 1/3, then we have the equation:

1/3 = ( (n - 4)/n)*((n - 5)/(n - 1))

Now let's solve this for n.

n*(n - 1)/3 = (n - 4)*(n - 5)

(n^2 - n)/3 = n^2 - 4*n - 5*n + 20

n^2 - n = 3*(n^2 - 9*n + 20)

n^2 - n = 3*n^2 - 27*n + 60

0 = (3*n^2 - n^2) - 27*n + n + 60

0 = 2*n^2 - 26*n + 60

The two solutions of this equation can be found with Bhaskara's equation:

n = \frac{-(-26) +- \sqrt{(-26)^2 - 4*2*60} }{2*2} = \frac{26+- 14}{4}

Then the two solutions are:

n = (26 - 14)/4 = 3

This is not an option, because we know for sure that we have 4 red counters, then this option can be discarded.

The other solution is:

n = (26 + 14)/4 = 40/4 = 10

Then we have n = 10, 10 counters in total.

4 0
2 years ago
I have two marks more than you do and the sum of both our marks is equal to 14 what are our marks
svet-max [94.6K]

your marks 9 my marks 5

Step-by-step explanation:

1/2 of 14 = 7

7 + 2 = 9

14 - 9 = 5

so your marks are 9 and mine are 5

Hope this helped ..

5 0
2 years ago
Guided Practice
levacccp [35]
I’m pretty sure the answer is A
7 0
3 years ago
Read 2 more answers
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