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Degger [83]
3 years ago
7

Amira is solving the equation x2 – 6x = 1. Which value must be added to both sides of the equation to make the left side a perfe

ct-square trinomial?
Mathematics
1 answer:
Lorico [155]3 years ago
7 0

Answer:

its 9

Step-by-step explanation:

I have  gotten it correct on ED

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Follow the process of completing the square to solve 2x2 + 8x - 12 = 0. After adding B2 to both sides of the equation in step 4,
valentina_108 [34]
 2x2 + 8x - 12 = 0
4 + 8x - 12 = 0
8x = 12 - 4
8x = 8
x = 1
4 0
3 years ago
Which expression is equivalent to x² + 2x + 2?
melisa1 [442]

Answer:

(x+1-i)(x+1+i)

Step-by-step explanation:

(x+1-i)(x+1+i)\\\\=(x+1)^2 -i^2~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=x^2 +2x +1 -(-1)\\\\=x^2 +2x +1+1\\\\=x^2 +2x +2

4 0
2 years ago
What is the product of x+2 and x-7? Write your answer in standard form.
Leto [7]
X^2-5x-14 
It is the correct answer I think
5 0
3 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0
3 years ago
(-6,-5); y= -4x+4 write an equation for the line in slope intercept form
PIT_PIT [208]

Answer:y=8x

Step-by-step explanation:

5 0
3 years ago
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