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3 years ago

Help With The Two Question

Mathematics

1 answer:

OverLord2011 [107]3 years ago

8 0

For 1st fig:
Angles whose measure is greater than angle 8 is:
<4,<5,<9

For 2nd fig:
Angles whose measure is less than angle 4 is:
<2,<5,<7

▶Explanation:
❇Statement of Exterior angle inequality theorem:
↪An exterior angle of a triangle is greater than either of the non-adjacent interior angles.

➡So for 1st fig ,< 4,<5,<9 were exterior angles of triangle which would obviously be greater angle than interior angle 8 by the theorem.

➡Similarly, for 2nd fig, <2,<5,<7 were non adjacent interior angles which would obviously be less in measure than exterior angle 4.In this case , see both triangles to not get confused.

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Estimated difference of 7 17/20 - 6 2/5

amm1812

Is always easier to subtract or add fractions with the same denominator, so
6 2/5 is the same as 6 8/20
I would suggest turning them both to improper fractions,
(You multiply 6 by the denominator 20 and get 120 then add 8)
6 8/20 = 128/20
and then do the same with 7 17/20 (Mutiply 7 and 20 and then add 17)
7 17/20 = 157/20

157/20 - 128/20 = 29/20 or 1 9/20

5 0

3 years ago

50 points! Show your work!

Evgesh-ka [11]

Answer:

a)19.28≈x (rounded to the nearest hundredth)

b)7.66≈x (rounded to the nearest hundredth)

c)x≈8.39(rounded to the nearest hundredth)

d)x≈36.87 (rounded to the nearest hundredth) and y=5

Step-by-step explanation:

I'm going to first assume that all of these are right triangles.

If you look at the hint, it says SOHCAHTOA

This stands for the trigonometric functions

SOH tells us that sine(θ)=opposite/hypotenuse

CAH tells us that cosine(θ)=adjacent/hypotenuse

TOA tells us that tangent(θ)=opposite/adjacent

(ps. θ, or theta, stands for any angle measure)

Now, let's look at problem a.

We have the value of the hypotenuse and the value of an angle. We want to find the side opposite from the angle. So, in this case, we want to use the sine function.

sin(40)=x/30

30*sin(40)=x

19.28≈x (rounded to the nearest hundredth)

We can solve the other problems in a similar fashion.

Problem b

We have the hypotenuse, an angle measure, and we want to find the adjacent side. This is telling us to use the cosine function.

cos(40)=x/10

10*cos(40)=x

7.66≈x (rounded to the nearest hundredth)

Problem c

We have an angle measure, an adjacent value, and we want to find the opposite length, so we're going to use the tangent function.

tan(40)=x/10

10*tan(40)=x

x≈8.39(rounded to the nearest hundredth)

Problem d

We need to first solve for x, the angle measure.

We have an opposite length, an adjacent length, so we can use the tangent function to solve for the missing angle

Let's set up an equation

tan(x)=3/4

Using $tan^{-1}$ or tangent inverse to cancel out the tangent, we get

x= $tan^{-1}$ (3/4)

x≈36.87 (rounded to the nearest hundredth)

Now, let's solve for y, the hypotenuse!

Both the sine and cosine functions work, so I'm just going to pick one.

sine(36.87)=3/y

y*sin(36.87)=3

y=3/sin(36.87)

y=5

Side note: Although I rounded the angle measure, when calculating the y value, on my calculator, I did not round the value. Don't round until the end on your calculator, but it's okay to round on your paper.

PS. I used degrees for the angle measures, not radians, so if you want to retry these problems, make sure your calculator is calculating degrees, not radians, or else you might get some funky answers.

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3 years ago

For the graph of the function below, identify the axis of symmetry, vertex and formula for the function

zhannawk [14.2K]

Well the first obvious thing is that the axis of symmetry is 0.5, so we can automatically cross out (C).

All the answers have the correct vertex, so lets find the formula for the function.

Fortunately, from my point of view, I can see two points that have their coordinates as integers, (-1, -3) and (2, 3), we can plug these into the already given "formulas" in the options (A), (B), and (D).

Out of the three choices, the formula in option (D) satisfies both coordinates, thus option (D) is correct.

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What is the area of the smaller circle if the radius is 2 feet?

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Answer:

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Step-by-step explanation:

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