Answer:
C and F**
Step-by-step explanation:
<u>Question</u><u>:</u>
In triangle JKL, the measure of angle L = 90°, KJ = 37, LK = 12, and JL = 35. What ratio represents the cosine of angle J?
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<u>Solution</u><u>:</u>
The triangle JKL should look like that in the attachment.
Cosine of J = adjacent side/hypotenuse
= LJ/KJ
= 35/37
Answer:
d = 200 miles
t = 1.5 hrs after start
Step-by-step explanation:
Set the origin at car a starting point.
equation for distance to car b
x = 250 - 60t
equation for distance to car a
y = 80t
distance between car a and car b
d = √((250 - 60t)² + (80t)²)
d = √(62500 - 30000t + 3600t² + 6400t²)
d = √(62500 - 30000t + 10000t²)
d = 100√(6.25 - 3t + t²)
setting the derivative to zero
0 = 100t - 150 / √(t² - 3t - 6.25)
The denominator cannot be zero, so the numerator must
0 = 100t - 150
150 = 100t
t = 1.5 hrs
d = √((250 - 60(1.5))² + (80(1.5))²)
d = √(160² + 120²)
d = 200 miles
Answer:
x = 16.5
Step-by-step explanation:
Firstly, open the brackets
6÷15x- 45 = 2÷3x+18
Rewrite the equation as:
6/15x-45 = 2/3x+18
cross multiply
6×3x+18 = 2×15x-45
18x+108 = 30x-90
collect like terms
18x-30x = -90-108
-12x = -198
divide both sides by -12
-12x/-12 = -198/-12
x = 33/2
x = 16.5
