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Marrrta [24]
3 years ago
13

in a right triangle, the length of the hypotenuse is 20 inches and the length of one leg is 15 inches. What is the length of the

other leg in inches?

Mathematics
2 answers:
BARSIC [14]3 years ago
7 0
You have to use the formula of Pythagoras

leg (call it AB) = √hypotenuse²-leg₁² = √20²-15² = √400-225 = √175 ≈ 13,22 inches
aleksklad [387]3 years ago
6 0
You can use the pythagorean theorem to solve this. To the nearest tenth, it is 13.23inches because 5 radical 7 is 13.228.

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Answer:

No it is wrong

Step-by-step explanation:

let's say the number is 15 is a substract 13 I get 2 but let's take 15 again of I add one I have 16 so it's incorrect

7 0
2 years ago
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Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1
defon
I'm guessing the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}

By the ratio test, the series converges if the following limit is less than 1.

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|

The first n terms in the numerator's denominator cancel with the denominator's denominator:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|

|x^n| also cancels out and the remaining factor of |x| can be pulled out of the limit (as it doesn't depend on n).

\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0

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3 0
3 years ago
What can you tell about a triangle when given three side lengths?
Genrish500 [490]
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2 years ago
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Answer:

<h2>See below</h2>

Step-by-step explanation:

Terms are variables in math.

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4x + 2x simply equals 6x.

I'm always happy to help :)

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