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Leviafan [203]
3 years ago
13

Use substitution to solve this problem m = -2, n = 4, p = 3, q = -82q - p =?​

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

- 19

Step-by-step explanation:

2q - p ( substitute p = 3, q = - 8 into the expression )

2(- 8) - 3

= - 16 - 3

= - 19

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Factor Completely: 10x + 15
tankabanditka [31]

Answer:

5(2x + 3)

Step-by-step explanation:

10x + 15 \\  \\  = 2 \times 5 \times x + 3 \times 5 \\ ( take \: common \: factors \: out )\\  = 5(2 \times x + 3) \\  \\  = 5(2x + 3)

3 0
2 years ago
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Please need help on this
IrinaVladis [17]

The first statement is true.

The second statement is false.

The third statement is true.


4 0
3 years ago
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Determine the factors of the expression x^2 - 9
Anuta_ua [19.1K]

Answer:

Step-by-step explanation:


The answer is B.


Use the sum-product pattern


2+3−3−9



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2+3−3−9x2+3x−3x−9


(+3)−3(+3)

Rewrite in factored form


(+3)−3(+3)


Solution:

(−3)(+3)

‘Hope it Helps!

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7B%20%5Cbegin%7Barray%7D%7B%7D%5Clarge%5Ctt%20The%20%20%5C%5C%20%20%5Ct
larisa86 [58]

Distance formula

\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

Now

#1

\\ \tt\Rrightarrow AB=\sqrt{(3-3)^2+(-2-8)^2}=\sqrt{100}=10units

#2

\\ \tt\Rrightarrow OK=\sqrt{(5-7)^2+(-2+2)^2}=\sqrt{4}=2units

#3

\\ \tt\Rrightarrow LM=\sqrt{(-4-4)^2+(6+4)^2}=\sqrt{64+100}=\sqrt{164}\approx 13units

#4

\\ \tt\Rrightarrow PC=\sqrt{(5-2)^2+(1-3)^2}=\sqrt{9+4}=\sqrt{13}=3.2units

#5

\\ \tt\Rrightarrow QR=\sqrt{(-2+10)^2+(3-9)^2}=\sqrt{64+36}=\sqrt{100}=10units

8 0
2 years ago
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It'll be a triangular prism right?
Harlamova29_29 [7]
Yes it would be a triangular prism
6 0
3 years ago
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