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Leviafan [203]
3 years ago
13

Use substitution to solve this problem m = -2, n = 4, p = 3, q = -82q - p =?​

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

- 19

Step-by-step explanation:

2q - p ( substitute p = 3, q = - 8 into the expression )

2(- 8) - 3

= - 16 - 3

= - 19

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Complete the statement using always, sometimes, or never. A rectangle is __________________ a rhombus.
Lesechka [4]
Hi!

A rectangle can sometimes be a rhombus if it has sides of all equal lengths. If a rectangle was a rhombus, it would also be a square. Furthermore, a square is always a rhombus.

Hope this helps! :)
7 0
3 years ago
*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
Ayden had a goal of finishing painting at least 80%, percent of the 500square meters of a house's walls by today. He actually fi
choli [55]

Answer:

yes Ayden Painted 415 square meters more than his goal

7 0
3 years ago
Determine the rate of change of the following coordinates
OleMash [197]

Answer:

-4

Step-by-step explanation:

 

4 0
3 years ago
What is an equation of the line that passes through the points (6, -3) and<br> (-6, -5)?
SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

The standard form of an equation for a straight line is y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).

We can calculate the slope from the two given points, (6,-3) and (-6,-5).  Slope is Rise/Run, where Rise is the change in y and Run is the change in x.

From the two given points, starting at (-6,-5) and going to (6,-3):

Rise = (-3 - (-5)) = +2

Run = (6 - (-6)) = 12

Rise/Run (slope) = 2/12 or 1/6

The equation becomes y = (1/6)x + b

We can find b by enterieng either of the two given points and solving for b.  I'll pick (6,-3):

y = (1/6)x + b

-3 = (1/6)*(6) + b

-3 = 1 + b             [Now you can see why I chose (6,-3)]

b = -4

The equation is y = (1/6)x - 4

Check this with a DESMOS graph (attached).

6 0
3 years ago
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