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ioda
4 years ago
10

Could anyone help me with this problem? I understand that you can cross multiply but is there a shorter way?

Mathematics
1 answer:
4vir4ik [10]4 years ago
8 0
There are several steps needed. I'm not sure this is what you call a shorter way, but I hope it helps!! :)

1) 3 lbs covers 1800 ft2 but we need to find how many ft2 1lb will cover. Divide # of lbs of seed available (3 lbs in this case) into the # of ft2 the available seed will cover (1800ft2 in this case):
1800ft2/3lbs=600ft2

So 1 lb covers 600ft2.

2) Now to find how many lbs 8400 needs. Divide the # of ft2 for 1 lb into the # of ft2 total (8400ft2 in this case):
8400/600ft2 (for 1lb) = 14 lbs

3) 14 lbs is now how many bags? The question does not say how many lbs in 1 bag.

IF ASSUMING the bags are 3lbs each, you divide the # of lbs per bag into the # of total lbs (14lbs in this case).

14lbs/3lb bags= 4.7 bags needed

IF 4lb bags:
14lbs/3lb bags= 3.5 bags needed

IF 5lb bags:
14lbs/5lb bags= 2.8 bags needed

IF 6lb bags:
14lbs/6lbs= 2.3 bags needed
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x = 11

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(x+5)2 = 32

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Ganezh [65]

The probability of drawing two blue marbles if the first marble is not replaced is 1/5

<h3>How to determine the probabilities?</h3>

<u>The probability of tossing a head and drawing a red marble</u>

The given parameters are:

White = 1

Blue =3

Red = 2

Total = 6

The probability of a head is

P(Head)= 1/2

The probability of drawing a red marble is

P(Red)= 2/6 = 1/3

The required probability is

P = P(Head) * P(Red)

This gives

P = 1/2 * 1/3

P =1/6

<u>The probability of drawing two blue marbles if the first marble is not replaced.</u>

Here, we have:

P(B1) = 3/6 = 1/2

P(B2) = 2/5

The required probability is

P = P(B1) * P(B2)

This gives

P = 1/2 * 2/5

P =1/5

Hence, the probability of drawing two blue marbles if the first marble is not replaced is 1/5

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Convert 0= 257PI/360 radians to degrees
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The answer is 128.5°

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