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2 years ago

How would i solve. been getting wrong

Mathematics

2 answers:

Wittaler [7]2 years ago

6 0

Answer:

2/15

Step-by-step explanation:

What you would want to do first is to get a common denominator for both fractions. What we can do is take the "below the waist" 3/5 and multiply it by 3 to get 9/15. Now that we have common denominators we can figure out the whole figure. If the torso is 4/15, and the BTW (Below the waist) is 9/15, if we add them together we get 13/15. So if we take a whole 15/15 and subtract the sum of the BTW and torso, we get 2/15.

Hope this helps.

And also please mark me brainliest.

Lisa [10]2 years ago

5 0

Answer:just find a common denomintor and add them

Step-by-step explanation:

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4vir4ik [10]

First figure is 75.4

4 0

2 years ago

Read 2 more answers

Solve the multi step literal equation: solve equation for A b^2A^2-3g=q

I am Lyosha [343]

Answer:

A = ± $\sqrt{\frac{q+3g}{b^2} }$

Step-by-step explanation:

Given

b²A² - 3g = q ( add 3g to both sides )

b²A² = q + 3g ( divide both sides by b² )

A² = $\frac{q+3g}{b^2}$ ( take the square root of both sides )

A = ± $\sqrt{\frac{q+3g}{b^2} }$

5 0

3 years ago

Time spent using e-mail per session is normally distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that

liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 11, \sigma = 3$

a. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 25, s = \frac{3}{\sqrt{25}} = 0.6$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.6}$

$Z = 0.33$

$Z = 0.33$ has a pvalue of 0.6293.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.6}$

$Z = -0.33$

$Z = -0.33$ has a pvalue of 0.3707.

0.6293 - 0.3707 = 0.2586

0.259 probability, rounded to three decimal places.

b. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.5 and 11 minutes?

Subtraction of the pvalue of Z when X = 11 subtracted by the pvalue of Z when X = 10.5. So

X = 11

$Z = \frac{X - \mu}{s}$

$Z = \frac{11 - 11}{0.6}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

X = 10.5

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.5 - 11}{0.6}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033.

0.5 - 0.2033 = 0.2967

0.297, rounded to three decimal places.

c. If you select a random sample of 100 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 100, s = \frac{3}{\sqrt{100}} = 0.3$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.3}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.3}$

$Z = -0.67$

$Z = -0.67$ has a pvalue of 0.2514.

0.7486 - 0.2514 = 0.4972

0.497, rounded to three decimal places.

5 0

3 years ago

The length of a rectangle is 5 more inches more than the width. The perimeter is 46 inches. Find the length and the width.

natta225 [31]

Answer: w = 9 inches

w + 5 = 14 inches

Step-by-step explanation:

5 0

2 years ago

Averigua: Cuantos habitantes tiene tu localidad y cuantos tu provincia Calcula A qué porcentaje de la población del Ecuador con

Diano4ka-milaya [45]

Answer:

La Provincia del Guayas comprime el 25.1% de la población de Ecuador. A su vez, la Ciudad de Guayaquil tiene una población igual al 15.58% de la población ecuatoriana.

Step-by-step explanation:

Dado que vivo en la Provincia del Guayas, y en la ciudad de Guayaquil, los datos de población solicitados son los siguientes:

-Provincia del Guayas: 4.387.434 habitantes, es decir, un 25.1% del total de la población de Ecuador, que es de 17.475.570 habitantes, conforme surge del siguiente calculo:

17.475.570 = 100

4.387.434 = X

4.387.434 x 100 / 17.475.570 = X

438.743.400 / 17.475.570 = X

25,10 = X

-Ciudad de Guayaquil: 2.723.665 habitantes, es decir, un 15.58% del total de la población de Ecuador, conforme surge del siguiente cálculo:

17.475.570 = 100

2.723.665 = X

2.723.665 x 100 / 17.475.570 = X

272.366.500 / 17.475.570 = X

15.58 = X

7 0

3 years ago