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erik [133]
3 years ago
14

Write an addition or subtraction fact. Then write a strategy you could use to add or subtract.

Mathematics
2 answers:
alexgriva [62]3 years ago
5 0
15+15

draw out circles or whatever strategy you use to add
Ne4ueva [31]3 years ago
4 0
2+2=4

You start with 2 and add an additional 2 to that. You now have 4.

I hope that helps!!!!!!

: )
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The volume of a cube whose edge is 3x, is​
diamong [38]

Answer:

27 { x}^{3}

Step-by-step explanation:

s represents one side of the cube

Volume of cube= (s)^3

= (3x)^3

= 27x^3

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3 years ago
Fraction 4/7 I want Decimal and Percent
alexgriva [62]

Answer:

The decimal of 4/7, when rounded to the hundredths, is 0.57. The percentage of 4/7, when rounded to the nearest hundredths, is 57.14%

Step-by-step explanation:

To get the decimal, you have to divide 4 by and you'll get your answer.

For the percentage, when rounded to the hundredths, you place the decimal two spots to the right (.57 turns into 57.14).

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In the linear equation y = 4x + 2, the value 2 represents which of the following?
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The answer is B: the y-coordinate of the y int.
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2 years ago
Write an equation to represent the situation below. Then explain what each part of the equation represents (the variables, the c
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3 0
3 years ago
A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
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