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kramer
3 years ago
10

One- sixth of the dairy cattle on a farm are in the barn. One- fourth of the beef cattle are in the barn. There are 12 dairy cat

tle and 16 beef cattle in the barn. How many more dairy cattle are on the farm than beef cattle
Mathematics
2 answers:
zepelin [54]3 years ago
8 0
There are 8 more dairy cattle on the farm than beef cattle.
Goshia [24]3 years ago
8 0
X = dairy cattle
y = beef cattle

1/6 x = 12
x = 72

1/4 y = 16
y = 64

so x-y = 72-64 = 8
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10 years ago, Rapunzel had 19 centimeters of hair, now her hair is 20,193 centimeters long, how long has her hair grown? in scie
zhuklara [117]

Answer:

Approximately 1*10^3

Step-by-step explanation:

20,193/19=1,062

5 0
3 years ago
Pls answer quickly, thanks!!
dybincka [34]

At the equilibrium price p, we can solve for the quantity of goods x :

demand = supply

5200 - 0.0005x = 2800 + 0.0003x

2400 = 0.0008x

x = 3,000,000

With this quantity of goods, the equilibrium price is

p = 5200 - 0.0005 (3,000,000)

p = 5200 - 1500

p = 3700

7 0
2 years ago
Solve for A if F=MA and F=10 and M=2.5
gogolik [260]

Answer:

\boxed{\sf A = 4}

Given:

F = MA

F = 10

M = 2.5

To Find:

Value of A

Step-by-step explanation:

\sf Substituting \ values \ of \ F \ and \ M \ in \ F = MA:

\sf \implies 10 = 2.5A

\sf \implies 2.5A = 10

\sf Dividing \ both \ side \ of \  2.5A = 10 \ by \ 2.5:

\sf \implies \frac{2.5}{2.5} A  =  \frac{10}{2.5}

\sf \frac{2.5}{2.5}  = 1 :

\sf \implies  A  =  \frac{10}{2.5}

\sf \frac{4 \times  \cancel{2.5}}{ \cancel{2.5}}  = 4 :

\sf \implies A = 4

3 0
3 years ago
Read 2 more answers
A pizza stand offer both hand- tossed and pan pizza. customer can add any combination of the six available topping.
photoshop1234 [79]
The correct choice would be 128.

If there are 6 options and the person can pick any number of toppings, we need to know the number of subsets that can be formed with 6. That would be 2^6 or 64.

Since there is a pan or hand-tossed option, we need to multiply 64 by 2 to find the total.
64 x 2 = 128
8 0
3 years ago
I’m not sure if I got the answer right and I need help on the table I’m lost
harkovskaia [24]

The given information permits us to calculate the circumference (C) of the wheel as follows

C=\frac{265}{5}=53in

Then (as you said correctly!) the same wheel will move

(53in)\cdot16=848in

after 16 rolls.

3 0
1 year ago
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