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3 years ago

HEEEEELP AGAIN LOL PLZ PLZ

1 answer:

3 0

I think it's -15/32, because that's the only one that makes sense to me.

-5/16 cannot be the answer, because -3/8 is one slot to the left of it.
-5/8 cannot be the answer, because if you convert it to 16ths, its -10/16.
-23/64 cannot be the answer, because it could also be one slot to the RIGHT of -3/8.

You might be interested in

1. Use a calculator to find all solutions in the interval (0, 2_). Round the answers to two decimal places. (Enter your answers

Anvisha [2.4K]

1) we know that sin2x=2sinxcosx, so sinxcosx=(1/2)sin2x, but sinxcosx=0.027
(1/2)sin2x=0.027, sin2x=0.054, arcsin(0.054)=2x, 3.09=2x, x=1.54 degree (x is in (0, 2), it is verified)

4 0

3 years ago

Help, I am so confused. Triangle Inequalities <br> Please and Thank you

Sav [38]

The Triangle Inequality Theorem says: Any side of a triangle must be shorter than the other two sides added together. The triangle inequality states that for any triangle, the sum of the lengths of any two sides must be greater than or equal to the length of the remaining side.

7 0

3 years ago

La probabilidad de que un dia cualquiera, carlos almuerce pollo frito es de 0,4. La probabilidad de que almuerce hambuergues es

MAXImum [283]

Answer:

0.6

Step-by-step explanation:

La fórmula para calcular la probabilidad de dos eventos se da como:

P (A⋃B) = P (A) + P (B) - P (A ⋂ B)

De la pregunta, sabemos que:

Probabilidad de que Carlos haya comido pollo frito: P (C) = 0.4.

Probabilidad de que Carlos coma una hamburguesa para el almuerzo: P (H) = 0.3.

Probabilidad de que Carlos almorce pollo frito y hamburguesa el mismo día: P (C ⋂ H) = 0.1.

Probabilidad de que Carlos coma pollo frito o hamburguesa para el almuerzo:

P (C ⋃ H) =?

Por lo tanto, aplicando nuestra fórmula:

P (C ⋃ H) = P (C) + P (H) - P (C ⋂ H)

P (C ⋃ H) = 0.4 + 0.3 - 0.1

P (C ⋃ H) = 0.6

6 0

3 years ago

How many solutions does 6 + x/5 = x/5 -5- 3x/10 have? A. Two solutions B. One solution C. No solutions D. Infinitely many soluti

MrRa [10]

Answer: A I think

Step-by-step explanation:

7 0

3 years ago

find the t values that form the boundaries of the critical region for a two-tailed test with a=.05 for n=6 n=12

AlexFokin [52]

Answer:

n=6

"=T.INV(1-0.025,5)", and we got the critical values given by: $t_{critical}=\pm 2.5706$

n=12

"=T.INV(1-0.025,11)", and we got the critical values given by: $t_{critical}=\pm 2.201$

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

For n=6

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the t distribution with df=n-1=6-1=5 degrees of freedom, a value that accumulates $0.05/2=0.025$ of the area on each tail. We can use excel or a table to find it, for example the code in Excel is:

"=T.INV(1-0.025,5)", and we got the critical values given by: $t_{critical}=\pm 2.5706$

For n=12

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the t distribution with df=n-1=12-1=11 degrees of freedom, a value that accumulates $0.05/2=0.025$ of the area on each tail. We can use excel or a table to find it, for example the code in Excel is:

"=T.INV(1-0.025,11)", and we got the critical values given by: $t_{critical}=\pm 2.201$

3 0

4 years ago