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allochka39001 [22]
3 years ago
15

PLease help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Mathematics
2 answers:
Viefleur [7K]3 years ago
8 0
I answered this above cause there was already 2 people typing, but then 1 quit, but the answer is p=8
~Hope this helped~
matrenka [14]3 years ago
3 0
P=8
Hope This Helps!
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A dress is marked up 16 2/3 to a final price of 140. what is the original price
rewona [7]
163.38

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6 0
2 years ago
A piggy bank contains only quarters and dimes. A representative sample has 6 quarters and 2 dimes. If there are 56 coins in the
nadezda [96]

Answer:

2

Step-by-step explanation:

Method- 56-25=31-25=6

I subtracted 25 until I cant no more so I only did it 2 times so 2 quarters are in the piggy bank.

Quarters-2

Then since the remainder was 6 that means there was only 1 penny and 1 nickel.

Pennies- 1

Nickels-1

8 0
2 years ago
If c=25 and B=75 degrees, find a. Round to the nearest tenth.
worty [1.4K]

Answer:

a=6.9

Step-by-step explanation:

Since you know that C is a right angle, you can use the Law of Sines to find a. The first step is to find the size of the angle A, which is 180-74-90=16. Now, you set up a ratio that involves 3 knowns and one unknown to get \frac{\sin(90^\circ)}{25} = \frac{\sin(16^\circ)}{a}, which after cross multiplying yields a=\sin(16^\circ)\cdot25\approx 6.9. PM me if you have any questions?

5 0
3 years ago
George spent $169.82 at the sports store.he gave the clerk 2 $100.how much change should George receive
Anestetic [448]
 $200.00 (George gave to the clerk)
-$169.82 (What George spend)
______________
 $30.18

George will receive $30.18 from the clerk.

Hope it help! 
3 0
3 years ago
Read 2 more answers
PLEASE HELP:
Lady bird [3.3K]

Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.

Explanation:

(A)

From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).

If a shape rotate 90 degree counterclockwise about the origin, then,

(x,y)\rightarrow (-y,x)

J(-4,1)\rightarrow J'(-1,-4)

K(-4,-2)\rightarrow K'(2,-4)

L(-3,-1)\rightarrow L'(1,-3)

Therefore, the vertex of imare are  J'(-1,-4),  K'(2,-4) and  L'(1,-3). The graph is shown in figure (1).

(B)

If a figure reflect across the y-axis then,

(x,y)\rightarrow (-x,y)

J(-4,1)\rightarrow J''(4,1)

K(-4,-2)\rightarrow K''(2,-4)

L(-3,-1)\rightarrow L''(3,-1)

Therefore, the vertex of imare are  J''(4,1),  K''(2,-4) and  L''(3,-1). The graph is shown in figure (2).

8 0
3 years ago
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