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juin [17]
3 years ago
5

If f(x) = 2x2 - x, find f(-3).

Mathematics
2 answers:
jonny [76]3 years ago
7 0
F(x) = 2x^2 - x
if x=-3

f(-3) = (2*(-3)^2) - (-3)
f(-3) = (2*9) + 3
f(-3) = 18 + 3
f(-3) = 21
Sergio [31]3 years ago
7 0

Answer: 21

Step-by-step explanation: because i got it right

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State the domain and range of the relation. Determine whether the relation represents a function.
dangina [55]

Answer:

Domain {-2,0,2}

Range {-2,0,2}

Relation is a Function

Step-by-step explanation:

We are given a relation:

{ (-2,-2) , (0,0) , (2,2) }

Domain can be defined as the all possible values of x for a relation. It is considered as a set of all first values of the ordered pairs of a given relation.

Domain of the given relation is {-2,0,2}

Range can be defined as all possible value of y which corresponds to the values of x in the domain. It is considered as a set of all second values of the ordered pairs of a given relation.

Range of the given relation is {-2,0,2}

A relation is a function if only there is one value of y for each value of x. If in the set of ordered pair of the relation, the value of x gets repeated, then the relation is not a function.

As no values of x are getting repeated, the relation is a function.

4 0
3 years ago
Which equation has a solution of 26?
lys-0071 [83]

Answer:

x=−  2/3     =−0.667

x=4

Step-by-step explanation:

3 0
4 years ago
How do I write 435 in expanded from
SVEN [57.7K]

Answer : 400 + 30 + 5

Step - by - step explanation : To write something in expanded form means to write the number individually. " To see the math value of individual digits ".

4 --> Since it's in the hundreds place that means the number is 400 !

3 --> Since it's in the tenths place that means the number is 30 !

5 --> Since it's the first digit that means it stays as the number 5 !

Hope this helped ! <33

Take care happy holidays ! Contact me if you need more help on this ! ( If you want )

4 0
2 years ago
Find the derivative of 3e^y+x=y
Sindrei [870]

You have the following function:

y=3e^y+x

Derivate implictly the previous expression, as follow:

y^{\prime}=3e^yy^{\prime}+1

Where you have used that:

(e^y)^{\prime}=e^yy^{\prime}

Then, the implicit derivative of the given expression is:

y^{\prime}=3e^yy^{\prime}+1

Next, solve for y' as follow:

\begin{gathered} y^{\prime}-3e^yy^{\prime}=1 \\ (1-3e^y)y^{\prime}=1 \\ y^{\prime}=\frac{1}{1-3e^y} \end{gathered}

4 0
1 year ago
Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi
miss Akunina [59]

Answer:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

Step-by-step explanation:

1st boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

Equation:

y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1

Solve:

c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}

Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0

Equation:

y=ax^2+c

The y-coordinate of the vertex:

y_v=a\cdot 0^2+c\Rightarrow c=-7

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-7\\ \\64a-7=1

Solve:

a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7

Parabola equation:

y=\dfrac{1}{8}x^2 -7

System of two equations:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

7 0
3 years ago
Read 2 more answers
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