Help please. l 4/3s-7 l - 8 > 3
1 answer:
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Answer:
x+3 is not a factor
Step-by-step explanation:
A graphing calculator shows the expression has a zero at x=3 and no other real zeros. If x+3 were a factor, there would be a zero at x = -3.
x+3 is not a factor of the expression.
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You can check to see if x+3 is a factor by evaluating the expression for x=-3. If (x+3) is a factor, x=-3 will make the function be zero.
3(-x³ +2x² +2x +3) = 3(((-x +2)x +2)x +3) = 3(((-(-3)+2)(-3) +2)(-3) +3)
= 3((-15+2)(-3) +3) = 3(39 +3) = 126 ≠ 0
The expression evaluates to 126 at x=-3, so x+3 is NOT a factor.
Answer:
x = 4.45 or x = - 4.45
Step-by-step explanation:
Here are the steps:
Substitute the values,
÷ 2 × 1
x = 2 ± √6
x = 4.45 or x = - 4.45
<em>good luck, i hope this helps :)</em>