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adell [148]
4 years ago
12

Synthetic division of (×3-125)÷(×-5)​

Mathematics
1 answer:
vodka [1.7K]4 years ago
7 0

Answer:

I believe that it might be 24.4

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Helppppppp ASAP plsss
zhuklara [117]

If p = 2, insert the value of p.

2^3 = 2 x 2 x 2 = 4 x 2 = 8

so p^3 = 8

6 0
3 years ago
Evaluate 18 + 4 ÷ 2 − 8. (5 points) Group of answer choices 2 8 12 3
cupoosta [38]

Answer:

=12

Step-by-step explanation:

See the steps below:)

5 0
3 years ago
Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3
omeli [17]
\frac{tan^2x}{1+cot^2x}+\frac{cot^2x}{1+tan^2x}=sec^2x\ cosec^2x-3\\\\L=\frac{tan^2x(1+tan^2x)+cot^2x(1+cot^2x)}{(1+cot^2x)(1+tan^2x)}=\frac{tan^2x+tan^4x+cot^2x+cot^4x}{1+tan^2x+cot^2x+tanxcotx}\\\\=\frac{tan^2x+cot^2x+tan^4x+cot^4x}{1+tan^2x+cot^2x+1}=\frac{tan^2x+2+cot^2x+tan^4x-2+cot^4x}{tan^2x+cot^2x+2}

=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1

=\frac{(sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{(sin^2x+cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{1}{sin^2x\ cos^2x}-\frac{2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1}{sin^2x}\cdot\frac{1}{cos^2x}-2-1\\\\=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R
3 0
4 years ago
Need help thinks its d​
lyudmila [28]

Answer: you're right, it is D.

Step-by-step explanation:

4 0
3 years ago
What is the equation of the line that is perpendicular to the y-axis and contains the point (-2,7)
Elenna [48]

Answer:

y = 7

Step-by-step explanation:

The straight line which is perpendicular to the y-axis will be either x-axis or parallel to the x-axis.

Now, the general equation for all straight line which is either x-axis or parallel to x-axis are given by y = c ........... (1), where c is any constant.

For c = 0 the line will be x -axis. therefore, y = 0, is the equation of x-axis.

Now, if the line (1) passes through the point (-2, 7), then the equation will be y = 7. (Answer)  

{Since, the point (-2,7) will satisfy the equation (1) and then c will be equal to 7.}

3 0
3 years ago
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