Answer:
Step-by-step explanation:
y=x²+7
vertex(0,7)
the length of latus rectum in a parabola equal to four times the focal length :
y=x²+7
focus X=-b/2a=0
focus Y=c- (b²-1)/4a=7+1/4=29/4
focus (0 , 29/4)
latus rectum is 29/4
(x-h)^2 = 4p (y-k) 4p is the length of the latus rectum with vertex(0,7)
(0-0)²=4p(29/4-7)
0=29p-28p=1p
the length of the latus rectum is 1
A parallel line has the same gradient
First you will need to rearrange the equation 10x+2y=-2
Then once you do that please comment
If you don’t know how please comment
Answer:
V=πr2h
3=π·72·9
3≈461.81412
Step-by-step explanation:
Mark me the brainliest PLZ.
The two equations graphs intersect and the points where they are touching are belonging to both graphs therefore solutions for both equations.
(2) points (x,y) are
(-1,0) (-1)^2. +0^2=1; 1=1 ✔️
0=-1+1; 0=0✔️
(0, 1). (0)^2. +1^2=1; 1=1 ✔️
1=0+1; 1=1 ✔️
Answer:
QR = 17 cm
Step-by-step explanation:
Δ RST is a 5- 12- 13 triangle with hypotenuse RT = 13 cm , then
TS = 5 cm and PT = 2 × 5 = 10 cm
So PS = 10 + 5 = 15 cm
PS is parallel to the vertical line from vertex Q and intersects the horizontal line projected from SR of length 20 - 12 = 8 cm
Using the right triangle formed calculate QR using Pythagoras' identity
QR² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )
QR = 
= 17
