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vodomira [7]
3 years ago
8

Ethan has a box of assorted tea bags. There are seven green tea bags, six peppermint tea bags, five lemon tea bags, and six plan

tation mint tea bags in the box. Ethan predicts that when he picks a tea bag from the box without looking, he will draw a peppermint tea bag one-fourth of the time. Which activity would best allow Ethan to test his prediction?
a. Randomly select a tea bag from the box and see if it is a peppermint tea bag.
b. Randomly select and replace a tea bag 80 times. Then, observe how close to 20 times a peppermint tea bag is drawn.
c. Randomly select a tea bag. Then, continue to draw another tea bag until all six peppermint tea bags are drawn.
d. Randomly select and replace a tea bag 90 times. Then, observe how close to 24 times a peppermint tea bag is drawn.
Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0
<span>B. Randomly select and replace a tea bag 80 times. Then, observe how close to 20 times a peppermint tea bag is drawn. </span>
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Simplify: 7·(a+5)–30 =
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Answer:

7a + 5

Step-by-step explanation:

Distribute using PEMDAS.


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3 years ago
Plz i need help with this. It would really help if you help me with this (._.)
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Z is B and x is D. Hope this helps!








6 0
2 years ago
A duck has 1,100 feathers. It went for a swim in a pond and lost 2/100 of its feathers. How many feathers did it lose?
svetlana [45]

Answer:

It lost 22 feathers.

Step-by-step explanation:

To complete this problem, this expression will be used: 2x/100.

2(1100)/100 {Multiply 2 by 1100}

2200/100 {Simplify by cancelling out 100}

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2 years ago
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Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What is the square root of 95.54
vladimir2022 [97]
Well this is simple a calculator type problem...but if you are curious as the the algorithm used by simple calculators and such...

They use a Newtonian approximation until it surpasses the precision level of the calculator or computer program..

A newtonian approximation is an interative process that gets closer and closer to the actual answer to any mathematical problem...it is of the form:

x-(f(x)/(df/dx))

In a square root problem you wish to know:

x=√n  where x is the root and n is the number

x^2=n

x^2-n=0

So f(x)=x^2-n and df/dx=2x so using the definition of the newton approximation you have:

x-((x^2-n)/(2x)) which simplifies further to:

(2x^2-x^2+n)/(2x)

(x^2+n)/(2x), where you can choose any starting value of x that you desire (though convergence to an exact (if possible) solution will be swifter the closer xi is to the actual value x)

In this case the number, n=95.54, so a decent starting value for x would be 10.

Using this initial x in (x^2+95.54)/(2x) will result in the following iterative sequence of x.

10, 9.777, 9.774457, 9.7744565, 9.7744565066299210578124802523397

The calculator result for my calc is: 9.7744565066299210578124802523381

So you see how accurate the newton method is in just a few iterations. :P


5 0
3 years ago
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