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vodomira [7]
3 years ago
8

Ethan has a box of assorted tea bags. There are seven green tea bags, six peppermint tea bags, five lemon tea bags, and six plan

tation mint tea bags in the box. Ethan predicts that when he picks a tea bag from the box without looking, he will draw a peppermint tea bag one-fourth of the time. Which activity would best allow Ethan to test his prediction?
a. Randomly select a tea bag from the box and see if it is a peppermint tea bag.
b. Randomly select and replace a tea bag 80 times. Then, observe how close to 20 times a peppermint tea bag is drawn.
c. Randomly select a tea bag. Then, continue to draw another tea bag until all six peppermint tea bags are drawn.
d. Randomly select and replace a tea bag 90 times. Then, observe how close to 24 times a peppermint tea bag is drawn.
Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0
<span>B. Randomly select and replace a tea bag 80 times. Then, observe how close to 20 times a peppermint tea bag is drawn. </span>
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What number must multiply each side of the equation 25x=10 to produce the equivalent equation x = 25?
insens350 [35]

Answer:

Multiply both sides by \frac{5}{2}

Step-by-step explanation:

Given

\frac{2}{5}x = 10

Required

Get an equivalent of x = 25

To do this, we simply multiply through by \frac{5}{2}

\frac{5}{2} * \frac{2}{5}x = 10 * \frac{5}{2}

\frac{5*2}{2*5} x = 10 * \frac{5}{2}

\frac{10}{10} x = 10 * \frac{5}{2}

\frac{1}{1} x = 10 * \frac{5}{2}

x = 10 * \frac{5}{2}

x =\frac{10*5}{2}

x =\frac{50}{2}

x = 25

5 0
3 years ago
Which equation represents a proportional relationship?
Verizon [17]

y = 3 x equation represents a proportional relationship.

Answer: Option B

<u>Step-by-step explanation:</u>

A proportional variation represents a relationship between two variables x and y. It can be expressed in the form y=k x. Here, the ‘k’, the proportionality constant is equal to the slope m and the line goes through the origin

case A) y=2\left(x+\frac{1}{3}\right)

A linear equation that not passes through the origin and so not proportional variation

case B) y= 3 x

Is a linear equation but passes through the origin and so proportional variation

case C) y = - 3x+2

A linear equation that not passes through the origin and so not proportional variation

case D)  \text { D) } y=\frac{1}{2 x}

An inverse variation equation but not passes through the origin and so not proportional variation.

From these, equation option B is the proportion equation because in these equations, there is no addition and subtraction of any constant number. That’s why both these equations become proportional equations.

5 0
3 years ago
Read 2 more answers
What must be added to x² + 6x²-x+ 5 to make it exact divisible by (x + 3)​
maxonik [38]

Let f(x) = x² + 6x²-x+ 5 then ,

number to be added be P

then,

f(x) = x² + 6x²-x+ 5 +P

According to the qn,

(x+3) is exactly divisible by zero then,

R=0

comparing .. we get a= -3

now by remainder theorm

R=f(a)

0=f(-3)

0=(-3)² + 6(-3)²-(-3)+ 5 + P

0= 9 + 54 + 3 + 5 + P

-71=P

therefore, -71 should be added.

Hope you understand

4 0
2 years ago
Which expressions are equivalent to StartFraction 1 Over 36 EndFraction? Check all that apply. 3 Superscript negative 6 6 Supers
Elenna [48]

Answer:

6^-2

6^3/6^5

6^-9 *6^ 7

Step-by-step explanation:

We want the fractions equal to 1/36

We know that a^-b = 1/a^b

We also know that a^b / a^c = a^(b-c)

We also know that a^b * a^c = a^(b+c)

3^ -6 = 1/3^6 = 1/729

6^-2 = 1/6^2 = 1/36

6^3/6^5 = 6^(3-5) = 6^-2 = 1/6^2 = 1/36

6^2 / 6^-1 = 6^(2- -1) = 6^3 = 216

6*6^-2 = 6^(1-2) = 6^-1 = 1/6

6^-9 *6^ 7 = 6^(-9+7) = 6^ -2 = 1/6^2 = 1/36

5 0
3 years ago
Read 2 more answers
Solve the system of linear equations by substitution. y−x=0y−x=0 2x−5y=9
Naddik [55]
There are no solutions to 2x-5y=9 but if you are solving it by y=mx+b form than your answer would look like this: y=2/5x-9/5
6 0
4 years ago
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