How to solve the problem

Simplify 22 – 5(2x + 4).

Georgia [21]

Answer:

-10x+2

Step-by-step explanation:

22-5(2x+4)

22-10x-20

2-10x

-10x+2

4 0

3 years ago

Read 2 more answers

Jay on started off his penny collection with 1 penny. He then adds 5 pennies to his collection each day. How could you change th

nata0808 [166]

Answer:

By doubling each day

Step-by-step explanation:

Jay is increasing daily a fixed amount of pennies to his collection. That's an arithmetic series, because to obtain the next term you have to do an addition.

To get a geometric series or progression you have to find the next term through multiplication.

So, if he wants to convert his series into a geometric series, he'd have to double his contribution to his collection each day (as an example).

4 0

3 years ago

An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are $E(1)= ^9C_2$ places in which the other 2 red balls can be placed.

A red ball drawn third, there are $E(3)= ^7C_2$ places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are $E(5)= ^5C_2$ places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are $E(7)= ^3C_2$ places in which the other 2 red balls can be placed.

The total number of total event is $S= ^{10}C_3$

The probability that A selects the first red ball is

$P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}$

$P(A \text{wins})=\frac{36+21+10+3}{120}$

$P(A \text{wins})=\frac{70}{120}$

$P(A \text{wins})=0.5833$

6 0

3 years ago

Suppose p(a) = 0.40 and p(a 

sveticcg [70]

Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

$P(A\cup B)+P(A\cap B)=P(A)+P(B)$

For parts (a) and (b), you're given everything you need to determine $P(B)$ .

For part (c), if $A$ and $B$ are mutually exclusive, then $P(A\cap B)=0$ , so $P(A\cup B)=P(A)+P(B)$ . If the given probability is $P(A\cup B)=0.55$ , then you can find $P(B)=0.15$ . But if this given probability is for the intersection, finding $P(B)$ is impossible.

For part (d), if $A$ and $B$ are independent, then $P(A\cap B)=P(A)\cdot P(B)$ .

8 0

3 years ago

What are the solutions to. x^2 - x - 20 = 0

nignag [31]

Step-by-step explanation:

x² - x - 20 = 0

x² - (5-4) x - 20 = 0 

x² - 5x + 4x -20 = 0

x ( x - 5) + 4 ( x - 5) = 0

(x - 5) (x+ 4) = 0

Either. 

x - 5 = 0

x = 5

Or, 

x + 4 = 0 

x = -4

3 0

3 years ago