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Aleks [24]
3 years ago
9

Write 10 3/4 as a improper fraction

Mathematics
2 answers:
nexus9112 [7]3 years ago
6 0
Salutations!

To convert a mixed fraction an improper fraction, you need to know the following rules:

10 \frac{3}{4}

Multiply 10 and 4, and then add 3 to it.

10*4=40

40+3=43

Improper fraction = \frac{43}{4}

Hope I helped (:

Have a great day!
scoundrel [369]3 years ago
4 0
47/4 is your final answer
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2/3 / 3/4 = 8/9 or 0.888888 repeating.

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How do I solve the equation in an interval from 0 to 2π ? 9 cos 2t = 6​
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9\cos(2t)=6\implies\cos(2t)=\dfrac23

Using the fact that cos is 2π-periodic, we have

\cos(2t)=\dfrac23\implies2t=\cos^{-1}\left(\dfrac23\right)+2n\pi

That is, \cos(\theta+2n\pi)=\cos\theta for any \theta and integer n.

\implies t=\dfrac12\cos^{-1}\left(\dfrac23\right)+n\pi

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t=\dfrac12\cos^{-1}\left(\dfrac23\right)\text{ and }t=\dfrac12\cos^{-1}\left(\dfrac23\right)+\pi

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5 times 10.50 = $52.5

An additional $45

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An other additional $65

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The Social Justice Club is going to rent a mammoth barbeque to cook the hot dogs for the hot dog sale After contacting three ren
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Answer:

(A)Cost of Rental A, C= 15x

Cost of Rental B, C=5x+50

Cost of Rental C, C=9x+20

(B)

i. Rental C   ii. Rental A     iii. Rental B

Step-by-step explanation:

<u>Part 1</u>

Let x be the number of hours of the barbeque use by the club.

Rental A: $15/h

Cost of Rental A, C= 15hx

Rental B: $5/h + 50

Cost of Rental B, C=5x+50

Rental C: $9/h + 20

Cost of Rental C, C=9x+20

<u>Part 2</u>

The graph of the three models is attached below

<u>Part 3(11.05-4.30)</u>

If the barbecue's usage hour is from 11.05 to 4.30 when the football match ends.

Number of Hours between 11.05am and 4.30pm=4 hours 25 Minutes = 4.42 Hours

Cost of Rental A, C= 15x=15(4.42)=$66.30

Cost of Rental B, C=5x+50 =5(4.42)+50=$72.10

Cost of Rental C, C=9x+20=9(4.42)+20=$59.78

Rental C should be chosen as it offers the lowest cost.

<u>Part 4 (11.05-12.30)</u>

Number of Hours = 12.30 -11.05 =1 hour 25 Minutes = 1.42 Hours

  • Cost of Rental A, C= 15x=15(1.42)=$21.30 Cost of Rental B, C=5x+50 =5(4.42)+50=$57.10 Cost of Rental C, C=9x+20=9(4.42)+20=$32.78

Rental A should be chosen since it offers the lowest cost.

<u>Part 5</u>

If the barbecue is returned the next day, say after 24 hours

  • Cost of Rental A, C= 15x=15(24)=$360 Cost of Rental B, C=5x+50 =5(24)+50=$170 Cost of Rental C, C=9x+20=9(24)+20=$236

Rental B should be chosen as it offers the lowest cost.

6 0
3 years ago
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