Because most of the area under any normal curve falls within a limited range of the number line
Answer:
133
Step-by-step explanation:
Snellville
12v+14b = 796
General
14v+12b =738
We need to solve for v and b where v is how many on a van and b is how many on a bus
12v+14b = 796
14v+12b =738
Divide each equation by 2
6v+7b =398
7v+6b =369
Multiply the first equation by 7 and the second equation by -6
7(6v+7b) =7(398)
42v +49b =2786
-6(7v+6b) =369*-6
-42v -36b = -2214
Add these equations together
42v +49b =2786
-42v -36b = -2214
-------------------------------
13b = 572
Divide each side by 13
13b/13 = 572/13
b= 44
Now find v
6v+7b =398
6v +7(44)=398
6v +308 = 398
Subtract 308 from each side
6v = 90
Divide by 6
6v/6 = 90/6
v = 15
We want 2 b and 3 v
2b+3v = 2(44)+3(15) = 88+45=133
Answer:
$286
Step-by-step explanation:
220:100=2.2
2.2 x 30 = 66
220+66=286
-x+40=28
-x=-12 (subtract 40 from both sides)
Divide by -1(in both sides)because you cant have a negative age.
COLE is 12
To check plug in the values.
Define
v = value after t years.
Therefore the linear model is
v = mt + c
where
m = depreciation rate
t = years since purchase
c = constant
When t=0, v = 20,000, therefore
20000 = m(0) + c
c = 20000
When t=10, v = 2000, therefore
2000 = 10m + 20000
-18000 = 10m
m = -1800
Answer:
The linear model is
v = -1800t + 20000
