The balls have the same mass but the table-twnnis ball is much less dense then the golf ball.
Answer:
20 gallons were used from the tank with the octane rating of 80.
Step-by-step explanation:
Given : One tank of gasoline has an octane rating of 140 and another tank of gasoline has an octane rating of 80. To obtain a mixture of 60 gallons with an octane rating of 120.
To find : How many gallons should be used from the tank with the octane rating of 80?
Solution : Let x be the volume of gas whose octane rating is 140 and
y be the volume of gas whose octane rating is 80.
Then, we form the equation as:
(1)
or .........[3]
(2)
Now multiply equation (2) by 4
...........[4]
Subtract (4) from (3)
Put x in equation [4] we get,
Therefore, x=40 and y=20
So, 20 gallons were used from the tank with the octane rating of 80.
Answer:
the rate of change of the area is Ra= 80 mm² per second
Step-by-step explanation:
the area of a rectangle (A) is
A = L * W , L= length and W= width
if the width remains constant the change in the area is only due to the change in length , thus:
ΔA = Δ( L * W ) = W * ΔL , where ΔA represents the change in area and ΔL represents the change in length
ΔA = W ΔL
denoting Δt as the time required to change, and dividing both sides by Δt
ΔA/Δt = W ΔL/Δt
where Ra=ΔA/Δt = rate of change of the area and RL=ΔL/Δt rate of change of the length.
thus
Ra = W * RL
replacing values
Ra = W * RL = 8 mm * 10 mm/second = 80 mm² /second
Answer:
Michelle bought a pack of crayon for $3.25
Step-by-step explanation:
Number of packs = 5
The cost of a pack of crayons =
(Cost of 5 packs of crayon) / (number of packs of crayons)
The cost of a pack of crayons = ($16.25 ) / 5
The cost of a pack of crayons = $3.25
The answer is D. x=0 and x=4 because a way to determine the answer is by inputting all the choices for x they have and if any of them has the answer then choose that one