The correct option is (A) x^6 + x^5 - 2x^4 - 2x^3 + 3x^2 + 6x - 9
Explanation:
The product of two polynomials:
(x^3 + x^2 -3)(x^3 - 2x + 3)
Row1: x^6 x^5 -3x^3
Row2: -2x^4 -2x^3 6x
Row3: 3x^3 3x^2 -9
Add all of the above rows:
x^6 + x^5 - 3x^3 -2x^4 - 2x^3 + 6x + 3x^3 + 3x^2 -9
x^6 + x^5 - 2x^4 - 2x^3 + 3x^2 + 6x - 9 (Option A)
If exactly one woman is to sit in one of the first 5 seats, then it means that 4 men completes the first 5 seats.
No of ways 4 men can be selected from 6 men = 6C4 = 15
No of ways 4 men can sit on 5 seats = 5P4 = 120
No of ways 1 woman can be selected fom 8 women = 8C1 = 8
No of ways 1 woman can sit on 5 seats = 5P1 = 5
No of ways <span>that exactly one woman is in one of the first 5 seats = 15 * 120 * 8 * 5 = 72,000
No of ways 14 people can be arranged in 14 seats = 14!
Probability that exactly one woman is in one of the first 5 seats = 72,000 / 14! = 0.0000008259 = 0.000083%
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Angle m∠1 if formed by a tangent and secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)
Answer: m∠1=1/2(mJK-KL)
Total number of times she flipped a coin =200.
Total number of heads in the experiment=92
Total number of tails in the experiment=108
Therefore probability of the coun landing heads up in this experiment is 0.5
In the above experiment, the probability of the coin landing heads up is
P(H)= 92/200 = 0.46
In the above experiment, the probability of the coin landing tails up is P(T) = 108/200 = 0.54
The ratio obj represent the experimental probability of the coin landing heads up in this experiment
Therefore the correct option is 1.
Answer:
7x - 3
Step-by-step explanation:
3x+(4x-3)
Remove parenthesis
3x + 4x - 3
Combine like terms
3x + 4x = 7x
7x - 3
