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nadya68 [22]
3 years ago
11

Consider the quadratic equation below. 4x^2-5=3x+4 Determine the correct set-up for solving the equation using the quadratic for

mula.
Mathematics
1 answer:
Kipish [7]3 years ago
4 0
4x²-5=3x+4
4x²-3x-9=0

x=(3±√((-3)²-4*4*-9))/2*4

x=3±√(9+144) /8

x=(3±√153) /8

x=⅜±√153/8
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Answer:

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A = P ( 1 + r/n)^nt

A = final amount

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n = number of times interest applied per time period

t = number of time periods elapsed

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A = final amount = Unknown

P = initial principal balance = $7,000

r = interest rate = 4% = 0.04

n = number of times interest applied per time period = semi annually , n= 2

t = number of time periods elapsed = 3 years

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A = P ( 1 + r/n)^nt

A = $7,000 (1 + 0.04/2)²×³

A = $7,000( 1+ 0.04/2)⁶

A = $7,000( 1.02)⁶

A = $ 7,883.14

The amount in the account after 3 years = $ 7,883.14

B. Find the interest earned.

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The interest earned = $ 883.14

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