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nadya68 [22]
3 years ago
11

Consider the quadratic equation below. 4x^2-5=3x+4 Determine the correct set-up for solving the equation using the quadratic for

mula.
Mathematics
1 answer:
Kipish [7]3 years ago
4 0
4x²-5=3x+4
4x²-3x-9=0

x=(3±√((-3)²-4*4*-9))/2*4

x=3±√(9+144) /8

x=(3±√153) /8

x=⅜±√153/8
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the legs of a right triangle have lengths of 28 meters and 21 meters. the hypotenuse has a lenght of 5x meters. what is the valu
Luba_88 [7]
From the Pythagorean Theorem, we know that a^2+b^2=c^2
28^2+21^2=(5x)^2
784+441=25x^2
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7 0
3 years ago
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Solve to find x and y in the diagram. HELP PLEASE!!!
Mashcka [7]

6x = 90

  x = 90/6

  x = 15

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4(15) + 10y = 90

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Answer: Last option

x = 15, y = 3

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Mario invests 1,500 in a savings account that earns 2% interest a year. He also plans to set aside $50 cash a month. A:2100(1.02
Sedbober [7]

Answer:

<em>1500(1.02)^x  +   600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere

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x is in years

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Before the years even start, you are at 1500 ( present value).

The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).

The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).

We keep multiplying factors of (1.02) each time.

So for year x, you would have saved 1500(1.02)^x.

Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year.  12(50)=600.  

So the first year you would have 600.

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The third year you would have 600(3) or 1800.

Let's put this together:

1500(1.02)^x  +   600x

4 0
4 years ago
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