Answer:
K' = (8,-4) L' = (4,-7) M' = (1,-2)
Step-by-step explanation:
Simply take the x coordinates and the y coordinates and flip them.
For example, if you have A (2, 4) reflected across y=x, A' would be (4,2).
Let's start by identify a 30-60-90 triangle
If we compare those two traingles we can stablish the following relation:
![\begin{gathered} a\sqrt[]{3}=6\sqrt[]{3} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5Csqrt%5B%5D%7B3%7D%3D6%5Csqrt%5B%5D%7B3%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Therefore, a=6
u is the opposite side to the 90° angle, therefore
on the other hand, v is the opposite side to the 30° angles, so
Answer:
The highest degree of the following polynomial x²+3x-10 is 2
Answer:
Look in explanation
Step-by-step explanation:
I will assume that you're trying to solve for "x".
For number 1: 49+(5x+1) is a supplementary angle(180 degrees) so you can subtract 180-49 to get 131.
Now, 131 = 5x+1
-1 -1
130 = 5x
/5 /5
Now, we isolate the x to get x=26.
Number 2: There is a supplementary angle as well so we can put 5x+12+6x+3=180.
Now, combine the like terms to get 11x+15=180 so we now isolate x.
-15 -15
11x=165
/11 /11
x=15
Now, try the rest and set the terms to 180.
5x+1+8+4x=180
2x+1+x-10=180
6+x+5x=180
x+2+153=180(This is similar to #1)
CHECK YOU ANSWERS BELOW AFTER YOU HAVE ATTEMPED THE REST OF THE PROBLEMS.
3. x=19
4. x=63
5. x=29
6. x=25
A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)
The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi
the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles
It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°
