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3 years ago

What inequality matches the statement : A number is at most 40

Mathematics

2 answers:

Misha Larkins [42]3 years ago

8 0

Answer:

N ( a number) $\leq$ 40

Step-by-step explanation:

Or just say

N $\leq$ 40

konstantin123 [22]3 years ago

3 0

Answer:

x≤40

Step-by-step explanation:

x (x is number in this case)

x≤40

The special sign used has the line under it because it includes 40 as well (at most is used not less than).

:) Hope this helps :)

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Margo has a coin collection. She was given 1 coin as a gift, and she adds 3 coins per year. Which of the graphs below represents

gavmur [86]

Answer:

Option C) graph of line going through 1, 4 and 3, 10

Step-by-step explanation:

Let y equal to Margo's coin collection

Let x equal to number of years

At the begining x=0, y=1 → Point=(x,y)→Point=(0,1)

She adds 3 coins per year, then y=1+3x

At x=1, y=1+3(1)=1+3→y=4→Point=(x,y)→Point=(1,4)

At x=3, y=1+3(3)=1+9→y=10→Point=(x,y)→Point=(3,10)

The graph of line going through (1, 4) and (3, 10), then the option C is the correct.

4 0

3 years ago

Subtract (2x3 + 9x − 8) − (4x2 − 15x + 7).

STatiana [176]

2x^3 + 9x - 8 - (4x^2 - 15x + 7)....distribute thru the parenthesis
2x^3 + 9x - 8 - 4x^2 + 15x - 7....combine like terms
2x^3 - 4x^2 + 24x - 15 <==

7 0

3 years ago

Read 2 more answers

If a(2x-3)=bx+5 then the solution for x in terms of a and b is

Fudgin [204]

Answer:

x=(3a+5)/(2a-b)

Step-by-step explanation:

first we distribute the a to the 2x and -3

2ax -3a=bx+5

we move the -3a over by adding 3a

2ax=bx+5+3a

then we move the bx over

2ax-bx=5+3a

we can now group the left side like this

x(2a-b)=5+3a)

to find x all we must do is divide both sides by (2a-b)

x=(3a+5)/(2a-b)

7 0

3 years ago

How do you solve...0=-5t^2+20t+1

-Dominant- [34]

There were 2 solutions that i came up with. Here is the first one. I rearranged the eqaution by subtracting what is to the right of thr equal sign. Multiply the coefficeint of the first term by the constant 5 x (-1)= -5. Then you would find 2 factors of -5 whose sum equals the coefficient of the middle term which is 20. -5+1= -4 and -1+5=4. the eqaution then comes to 5t^2-20t-1=0. you would solve 5t^2-20t-1=0. you would divide both sides of the equal sign by 5. t^-4t-1/5=0. then t^2-4t=1/5. add 4 to both sides of the equation. so we get 21/5+ 4 + 4t -t^2=21/5. it then comes out to be t^2-4t+t=t-2^2. according to the law of transitivity it is t-2^2=21/5.

t =(20+√420)/10=2+1/5√<span> 105 </span><span>= 4.049 </span>.

4 0

3 years ago

carol can complete her neighborhood jog in 10 minutes. It takes 30 minutes to cover the same distance when she walks. If her jog

Travka [436]

Answer:

6mph

Step-by-step explanation:

In this question, we are asked to calculate the speed at which Carol jogs, given that she has a particular speed when she jogs greater than when she walks.

Firstly, we should understand that she is taking the same distance, whether she jogs or walks.

Now, let’s say her jogging rate is x mph, this means that her walking rate would be (x - 4)mph. This is because her jogging rate is 4mph faster than her walking rate.

The total distance covered when jogging is thus 10/60 * x, while her total distance covered when walking would be 30/60 * (x-4)[we convert the time to hours]

We equate both since they are same distance:

x/6 = (x -4)/2

2x = 6(x - 4)

2x = 6x - 24

4x = 24

x = 6mph

8 0

4 years ago