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ElenaW [278]
3 years ago
8

Write an equation perpendicular to x-4y=20 that passes through the point 2,-5

Mathematics
1 answer:
marshall27 [118]3 years ago
3 0

Answer:

  4x +y = 3

Step-by-step explanation:

Perpendicular lines have slopes that are the negative reciprocals of one another. When the equation of the line is written in standard form like this, the equation of the perpendicular line can be written by swapping the x- and y-coefficients and negating one of them. Doing this much would give you ...

  4x +y = (constant)

Note that we have chosen to make the equation read 4x+y, not -4x-y. The reason is that "standard form" requires the leading coefficient to be positive.

Now, you just need to make sure the constant is appropriate for the point you want the line to go through. So, it needs to be ...

  4(2) +(-5) = constant = 3

The line of interest has equation ...

  4x + y = 3

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A function, f(x) = 4x + 5, has a domain 0 < x < 50. What is its range?
Roman55 [17]

Answer:

f(x) = 4x+5 ; 0 ≤ x ≤ 50

 

The range is the possible output values of f(x)

 

4(0) + 5 = 5       smallest output value in range

4(50) + 5 = 55    largest output value in range

 

The outputs are between 5 and 55 including the endpoints so

the range is [5, 55]

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3 years ago
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4 years ago
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Answer:

6, 8, 10, 12, 18, 20

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Question IS in PICTURE!!!!
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3 years ago
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Solve this steps not needed
777dan777 [17]

Hi!

When you add a negative number, you really just subtract it. So let's solve this.

Convert the mixed numbers into improper fractions.

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\frac{83}{9}

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Hope this helps! :)

-Peredhel

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4 years ago
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