All categories

3 years ago

PLEASE HELP ASAP

Mathematics

1 answer:

tekilochka [14]3 years ago

6 0

X-y= 15
2y-x=2

Adding these two together:
Y=17
Therefore, x = 32

You might be interested in

Answer ASAP please

Vikki [24]

Answer:

h = 16 || solution after squaring: $x = -0.683$ or $x = -7.32$

steps by fieranswererft:

Given: $x^2+8x+5=0$

Take half of the x term and square it

$[8*\frac{1}{2} ]^2=16$

$x^2+8x+16=- 5+16$

$(x+4)^2=-5+16$

$(x+4)^2=11$

$x+4 = \pm \sqrt{11}$

$x = \pm \sqrt{11}-4$

$x = -0.683$ or $x = -7.32$

7 0

3 years ago

In the year 2000, the average cost of a computer could be modeled by the equation C = -5t2 + 750, where t is the number of years

elena55 [62]

Answer:

$\Delta C=-5t^2-250$

Step-by-step explanation:

Given:

The average cost of a computer in the year 2000 is given as:

$C=-5t^2+750$

The average cost of a computer in the year 2008 is given as:

$C=-10t^2+500$

Now, the difference in average cost between the years 2008 and 2000 can be calculated by subtracting the average cost in 2000 from the average cost in 2008.

Framing in equation form, we get:

Difference in average cost (ΔC) is given as:

$\Delta C=C_{2008}-C_{2000}\\\\\Delta C= (-10t^2+500)-(-5t^2+750)\\\\\textrm{Distributing the megative sign inside the second polynomial, we get:}\\\\\Delta C=-10t^2+500+5t^2-750\\\\\textrm{Grouping like terms, we get}\\\\\Delta C=(-10t^2+5t^2)+(500-750)\\\\\Delta C=-5t^2-250$

Therefore, the difference in the costs for a computer between 2008 and 2000 is $\Delta C=-5t^2-250$

7 0

4 years ago

A large brine tank containing a solution of salt and water is being diluted with fresh water. The relationship between the elaps

rewona [7]

Answer:

41.04

Step-by-step explanation:

thats the answer on khan academy :3 i hope this helps

6 0

3 years ago

Evaluate. 2^−2⋅(12⋅3)−5^3

Oduvanchick [21]

$\text{Hello there!}\\\\\text{Solve the equation:}\\\\2^{-2}\left(12\cdot 3\right)-5^3\\\\0.25(12\cdot3)-5^3\\\\0.25(36)-5^3\\\\9-5^3\\\\9-125\\\\\large\boxed{-116}$

4 0

3 years ago

Read 2 more answers

A model car is built on a scale of 2:21 of a real car . If the real car has a height of 1.7 meters , what is the height of the m

bogdanovich [222]

To get from the real value to the model value, you must divide by 21 and times by two (since 21/21 = 1 and 1 x 2= 2 in the ratio) this is the same as multiplying by the fraction 2/21.
So, 1.7 x 2/21 = 17/105 = 0.16m or 16cm

3 0

3 years ago