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Stels [109]
3 years ago
9

Hey say it back.....​

Mathematics
2 answers:
sineoko [7]3 years ago
4 0

Answer:

hey

Step-by-step explanation:

LekaFEV [45]3 years ago
3 0
Answer
Hey :)

Explanation
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What is the axis of symmetry of h(x)= 5x^2+40x+ 64?
andrezito [222]

Answer:

Axis of symmetry is  x = -4

Step-by-step explanation:

h(x)= 5x^2+40x+ 64

Use the formula for axis of symmetry:   x = -b/(2a)

Here,  a = 5,  b = 40,  c = 64

so

x = -40/(2*5) = -40/10 = -4

Axis of symmetry is  x = -4

3 0
3 years ago
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Which equality represents the proportion $10 is to 15 cans as $30 is to $45 cans?
Sladkaya [172]

Answer:

I'm guessing it's C because it's the only one that looks right

5 0
3 years ago
Help me plz I’ll give brainlist plz!!!!!!!!!!!
marishachu [46]

Answer:

answer is 10/3 thats the answer

5 0
3 years ago
You estimate the distance from your house to your school to be 1.6 miles. The actual distance is 1.9 miles. Find the percent err
Bezzdna [24]
To find percent error you use the following formula:
% Error =  \frac{final value - given value}{given value}
% error = (1.6 - 1.9)/1.9 * 100% = 15.79%
5 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
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