If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to (s o t)(-7)?

Mathematics

1 answer:

marishachu [46]3 years ago

8 0

Answer:

The correct answer is A) -439

Step-by-step explanation:

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What Passes through (6,-3) parallel to y= -2x-5?

Sveta_85 [38]

Answer:

y+2x=9 is the line passing through (6,-3) parallel to y=-2x-5

Step-by-step explanation:

In the question we are given with a point (6,-3) and a line $y=-2x-5$ . we have to find the line passing through given point and parallel to given line.\

formula used: equation of a line passing through a point(a,b) with slope m is given by $(y-b) = m(x-a)$ .

here we have (a,b)=(6,-3) and the slope of the line is slope of $y=-2x-5$

i.e, -2( coefficient of x).

therefore, substituting point and slope in formula we get $y+3 = -2(x-6)$

which simplifies to $y+3= -2x+12\\ y+2x=9$ is asked line equation

6 0

3 years ago

35. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.

Montano1993 [528]

Answer:

The linear equation for the line which passes through the points given as (-2,8) and $(4,6), is written in the point-slope form as $y=-\frac{1}{3} x-\frac{26}{3}$ .

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-2,8) and (4,6).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-2,8) and (4,6). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute $6 \& 8$ for $y_{2}$ and $y_{1}$ respectively, and 4&-2 for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows, $m=\frac{6-8}{4-(-2)}$

$\begin{aligned}&m=\frac{-2}{6} \\&m=-\frac{1}{3}\end{aligned}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-2 for $x_{1}$ , and 8 for $y_{1}$ in the above equation and simplify using the distributive property as follows, $y-8=-\frac{1}{3}(x-(-2))$\\ $y-8=-\frac{1}{3}(x+2)$\\ $y-8=-\frac{1}{3} x-\frac{2}{3}$$