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2 years ago

What are the solutions to this system of equations?

Mathematics

1 answer:

saveliy_v [14]2 years ago

4 0

Answer:

Step-by-step explanation:

The solution is at the points of intersections of the graphs

The graphs intersect at (- 3, 0 ) and (2, 5 ) , then

solutions are (- 3, 0 ) and (2, 5 )

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Ted, the postman, has 110 letters to deliver. If Ted can deliver 10 letters in 5 minutes,

valina [46]

Answer:

Step-by-step explanation:

There are 11 tens in 110, so 11 times 5 is 55.

8 0

3 years ago

Whats the quake root of 6

rewona [7]

I don’t get what you mean. Reword it

6 0

3 years ago

Lynn is trying to determine how far away Student B is from the balloon. He decides to use the

kaheart [24]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the image that illustrates the scenario is not given.

However, I can deduce that the question is about a right-angled triangle.

So, I will give a general explanation on how to find each of the side of the triangle, given a side and an angle.

For triangle A (solve for b)

Using cosine formula.

$\cos \theta = \frac{Adjacent}{Hypotenuse}$

$\cos 60= \frac{5}{b}$

Make b the subject

$b= \frac{5}{\cos 60}$

For triangle B (solve for b)

Using cosine formula.

$\sin \theta = \frac{Opposite}{Hypotenuse}$

$\sin 60= \frac{b}{5}$

Make b the subject

$b = 5\sin 60$

For triangle C (solve for b)

Using cosine formula.

$\tan \theta = \frac{Opposite}{Adjacent}$

$\tan 60= \frac{b}{5}$

Make b the subject

$b = 5\tan 60$

3 0

2 years ago

Read 2 more answers

What is the difference: 12÷4 x 3 12÷ 3 x 4

nikdorinn [45]

12 ÷ 4 x 3 = 3 x 3 = 9

12 ÷ 3 x 4 = 4 x 4 = 16

6 0

3 years ago

Read 2 more answers

What is the discontinuity and zero of the function f(x) = 3x^2 + x - 4 / x-1

7nadin3 [17]

Ans: Option (1) Discontinuity at (1, 7), zero at ( negative four thirds , 0)

Explanation:
Given function:
$f(x) = \frac{3x^2 + x - 4}{x-1}$

Now if we plug in the x = 1, we would have discontinuity as function goes to infinity.

Now for f(1):
$f(x) = \frac{3x^2 + x - 4}{x-1} \\ f(x) = \frac{3x^2 + 4x - 3x - 4}{x-1} \\ f(x) = \frac{x(3x+4)-1(3x+4)}{x-1} \\ f(x) = \frac{(x-1)(3x+4)}{(x-1)} \\ f(x) = 3x+4 \\ now ~ insert ~ x=1: \\ f(1) = 3(1) + 4 = 7 \\ It~means~discontinuity~at~(1,7).\\ Now~let~us~find~zeros.\\ put~ f(x) = 3x+4 ~ equals~ to ~zero. \\ =\ \textgreater \ ~3x+4 = 0 \\ =\ \textgreater \ ~ x = \frac{-4}{3} \\ Hence~zeros=( \frac{-4}{3}, 0)$

5 0

3 years ago