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stira [4]
3 years ago
9

A microscope has a setting that magnifies an object so that it appears 100 times as large when viewed through the eyepiece. If a

tiny insect is 0.095 cm long, his long will the insect appear in centimeters through the microscope? Explain how you know.
Mathematics
2 answers:
Jlenok [28]3 years ago
8 0

Answer:

The length of the insect appear 9.5 centimeters.

Step-by-step explanation:

Consider the provided information.

A microscope has a setting that magnifies an object so that it appears 100 times as large when viewed through the eyepiece.

It is given that the length of tiny insect is 0.095 cm

Now to find the length of the insect through microscope, simply multiply the number 0.095 with 100.

0.095×100

Shift the decimal point to the right as many places as the factor contains zeros.

Here the factor contains 2 zero so move decimal point 2 place right.

0.095×100=9.5

Thus, the length of the insect appear 9.5 centimeters.

3241004551 [841]3 years ago
5 0

The length of the insect in the final image is \boxed{9.5\text{ centimeter}}.

Further explanation:

In the question it is given that if an object is viewed under a microscope then the object appears 100 times large than its original size.

It is given that the length of a insect is 0.095 centimeter.

This question is based on the concept of multiplication of decimals.

Consider the length of the insect as x\text{ cm}.

Since, the length of insect is 0.095 centimeter so, trhe value of x is 0.095.

As per the question the size of the final image is 100 times large as the original size so, the size of final image is calculated as follows:

\boxed{S=x\times 100}

Substitute 0.095 for x in the above equation.

\boxed{\begin{aligned}S&=x\times 100\\&=0.095\times 100\\&=9.5\end{aligned}}

From the above calculation it is concluded that the length of the insect in the final image is 9.5\text{ centimeter}.

Therefore, the length of the insect in the final image is \boxed{9.5\text{ centimeter}}.

Learn more:

1. Learn more about numbers brainly.com/question/4736384

2. Learn more about scientific notation of numbers brainly.com/question/4736384

Answer details:

Grade: Junior school

Subject: Mathematics

Chapter: Simplification

Keywords: Microscope, insect, cenimeter, magnifies, 0.095cm, 100 times, eyepiece, viewed, 9.5cm, simplification, multiplication, decimals, final image.

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Step-by-step explanation:

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Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

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Z = \frac{X - \mu}{\sigma}

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4 0
3 years ago
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Answer:

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Formula for standard deviation is;

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σ = √((70 - 36.67)² + (40 - 36.67)² + (30 - 36.67)² + (40 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (10 - 36.67)²)/(9 - 1)

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B) For various birds;

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Answer:

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Step-by-step explanation:

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