Rewrite then factor as a difference of cubes:
1 - 64<em>x</em>³ = 1³ - (4<em>x</em>)³
= (1 - 4<em>x</em>) (1² + 4<em>x</em> + (4<em>x</em>)²)
= (1 - 4<em>x</em>) (1 + 4<em>x</em> + 16<em>x</em>²)
(^3-^2+2)D=0
D^2+D^2+2D=0
2D^2+2D=0
a = 2; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·2·0
Δ = 4
D1=−b−Δ√2aD2=−b+Δ√2a
Δ−−√=4√=2
D1=−b−Δ√2a=−(2)−22∗2=−44=−1
D2=−b+Δ√2a=−(2)+22∗2=04=0
Answer:
no
Step-by-step explanation:
you cannot divide zero into two equal parts because there is nothing there to start. Since Pablo has no candy, he cannot divide it into two piles because there isn't anything to divide.
First we have to find the vertex (h,k) h is also x and it also is the a xis symmetry
1st: group the number
(X2+6x)-9
2nd: use b/2
6/2 = 3 , 3^2= 9
(X2+6x+9)-9-9
(X2 + 3)-18
Vertex is 3,-18 so the symmetry is 3
I pretty sure its D because its not the other ones can you send me a message real quick too
