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NemiM [27]
3 years ago
8

Lines m and n are parallel.

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0

Answer:

c

Step-by-step explanation:

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A taxi ride cost $2 for the first 1/5 of a km and 40 cents for each additional fifth of a km. Dan has $9.60. What is the longest
Harlamova29_29 [7]

Answer:

4 kilometers

Step-by-step explanation:

<em>First! Let's create an equation, with our variable (x) representing the number of additional fifth kilometers Dan can afford. </em>

2 + 0.40x = 9.60

<em>Now, we have to solve for our x value by subtracting 2 from both sides.</em>

0.40x = 7.60

<em>Next, we can divide both sides by 0.40 to find out what our x value is equal too.</em>

x = 19

<em>Don't forget this x value is just for the number of </em><em>additional</em><em> fifth kilometers Dan can afford on top of his first fifth mile.</em>

<em />

<em>So! Dan can afford 20 fifth kilometers, which in turn in is 4 kilometers in total. </em>

<em />

Hope this Helps! :)

<em>Have any questions? Ask below in the comments and I will try my best to answer.</em>

-SGO

5 0
3 years ago
Which fraction is the bigger fractured 2/10 or 23/100
lesantik [10]
Answer: 23/100

Find the greatest common factor (gcf)

Which is 100 so 23/100 is done

2/10 multiply 10 times 10 to get 100

Multiply 2 times 10 which is 20/100

23/100 is greater
4 0
3 years ago
Read 2 more answers
1) Jennifer and Ryan are selling cheesecakes for a school fundraiser. Customers can buy New York
ella [17]
Add 32+76 and it give you 108
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3 years ago
Events without replacement are independent events.<br><br> false<br><br> true
Elina [12.6K]

Answer:

True

Step-by-step explanation:

When sampling is done with replacement, then events are considered to be independent, meaning the result of the first pick will not change the probabilities for the second pick. Without replacement: When sampling is done without replacement, each member of a population may be chosen only once.

7 0
3 years ago
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Ray PQ bisector segment CD at its midpoint
pantera1 [17]

Answer:

<h3><u>Diagram</u><u>:</u><u>-</u>\Huge{\downarrow}</h3>

setlength{\unitlength}{1cm}\begin{picture}(20,15)\thicklines\qbezier (1, 0)(1,0)(5,0)\put (3,5){\vector (0,-1){6}}\put (0.5,-0.2){\sf C}\put(5.1,- 0.2){\sf D}\put (3,5.2){\sf P}\put (3.3,-1.5){\sf Q}\end{picture}

8 0
3 years ago
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