Answer: x=0
Step-by-step explanation:
4x-3x = 0
Answer:
x + 13 = 25
Step-by-step explanation:
Se puede representar "un número" con x.
x
"Adiciona" significa +.
x + 13
"El resultado" significa =.
x + 13 = 25
Solution:
Step 1:
We will calculate the volume of ice cream in the single scoop
The volume of the ice cream will be

By substituting the values, we will have

Step 2:
We will use the formula below to calculate the volume of the two scoops of ic cream

Step 3:
We will use the formula below to calculate the volume of the three scoops of ic cream

For the first ice cream with one scoop

For the second ice cream with two scoops

For the third ice cream with three scoops

Hence,
The final answer is
The triple sold at $5.50 has the best value because it has the lowest price of $0.21 per cubic inch of the ice cream
Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Answer:
First brand of antifreeze: 21 gallons
Second brand of antifreeze: 9 gallons
Step-by-step explanation:
Let's call A the amount of first brand of antifreeze. 20% pure antifreeze
Let's call B the amount of second brand of antifreeze. 70% pure antifreeze
The resulting mixture should have 35% pure antifreeze, and 30 gallons.
Then we know that the total amount of mixture will be:

Then the total amount of pure antifreeze in the mixture will be:


Then we have two equations and two unknowns so we solve the system of equations. Multiply the first equation by -0.7 and add it to the second equation:



+

--------------------------------------



We substitute the value of A into one of the two equations and solve for B.

