Answer:
2.40%
Explanation:
Density of a substance is given as the mass divided by the volume ,
Hence from the question ,
density of sulfuric acid = 1.35 g/mL
i.e.
1mL of sulfuric acid solution = 1.35 g of sulfuric acid ,
Hence,
1000mL of sulfuric acid solution = 1.35 * 1000 g of sulfuric acid,
i.e.
1000mL of sulfuric acid solution = 13500 g of sulfuric acid,
Now, Molarity of a solution is given by the moles of solute per liter of the solution .
Hence,
M = moles of solute / volume of solution (in L)
From question , '
3.43 M of sulfuric acid ,
Hence,
In 1 L of solution , 3.34 moles of sulfuric acid are present,
Now,
Moles are calculated as the given mass divided by the molecular mass.
The molecular mass of sulfuric acid is 98 g /mol
moles = ( mass / molecular mass )
therefore,
mass = moles * molecular mass
i.e.
mass of sulfuric acid = 3.34 mol * 98 g/mol = 327.32 g
Now, to calculate the mass percentage of sulfuric acid , is given by the mass of sulfuric acid divided by the mass of the total solution multiplied by 100.
therefore,
mass of sulfuric acid = 327.32 / 13600 * 100
Hence, mass of sulfuric acid = 2.40%
