The required solution is prepared taking 0.1 mL of 10 M stock NaOH solution and placing it into a 100 mL volumetric flask. The solution is made up to 100 mL with distilled water in order to have a 100 mL solution of 10 mM NaOH solution.
The required solution is prepared by diluting a given volume of the stock solution.
Using the dilution formula: C₁V₁ = C₂V₂
Where C₁ = initial concentration of solution
V₁ = initial volume of solution
C₂ = final concentration of solution
V₂ = final volume of solution
From the given values:
C₁ = 10 M, V₁ = ?, C₂ = 10 mM = 0.01 M, V₂ = 100ml
Making V₁ subject of the formula in the dilution formula:
V₁ = C₂V₂/C₁
V₁ = 0.01 * 100 / 10
V₁ = 0.1 mL
Therefore, the volume of stock solution needed to prepare 100 mL of 10 mM NaOH solution is 0.1 mL.
0.1 mL of 10 M stock NaOH solution is taken and put into a 100 mL volumetric flask. The solution is made up to 100 mL with distilled water in order to have a 100 mL solution of 10 mM NaOH solution.
Learn more more about preparation of solutions and dilution at : brainly.com/question/24549357
Atomic mass Boron ( B ) = 10.811 u.m.a
10.811 g -------------- 6.02x10²³ atoms
5.40 g ----------------- ?? atoms
5.40 x ( 6.02x10²³) / 10.811 =
3.0069x10²³ atoms
Answer:
The cathode reaction is NiO2+H2O+2e−→Ni(OH)2+2OH−.
33.6 moles are needed to completely react with 84.0 moles of O2
