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Gwar [14]
3 years ago
10

10. Write the formula for the compounds: copper (1) chloride and copper (II) chloride

Chemistry
1 answer:
Natali [406]3 years ago
3 0

Answer:

Copper(II) chloride (CuCl2) reacts with several metals to produce copper metal or copper(I) chloride (CuCl) with oxidation of the other metal.

Explanation:

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Calculate the % yield if the amount of alum obtained was 18.28 g and the expected amount was 19.93 g.
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4 years ago
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Two waves were analyzed with some high-tech instrumentation. The first wave was found to have a wavelength of 3 x 10 m and the s
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Explanation:

The first wave was found to have a wavelength of 3 x 10⁵ m and the second wave had a wavelength of 3 x 10⁴ m

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The relation between frequency and wavelength is given by :

c=f\lambda

Let f₁ and f₂ be the frequency of wave 1 and wave 2.

f_1=\dfrac{c}{\lambda_1}\\\\f_1=\dfrac{3\times 10^8}{3\times 10^5}\\\\=1000\ Hz

And

f_2=\dfrac{c}{\lambda_2}\\\\f_2=\dfrac{3\times 10^8}{3\times 10^4}\\\\=10000\ Hz

Hence, the wave having less wavelength will have higher frequency. The wave having wavelength 3 x 10⁴ m will have higher frequency.

8 0
3 years ago
Select the statement(s) that describe the characteristics of transition metals. a. Transition metals have partially filled d sub
yan [13]

Answer: The correct option is A,

--> a.) Transition metals have partially filled d subshells.

Explanation:

Transition elements are all metals of economic importance. They are found in the d- lock of the periodic table between group 2 and 3. They occupy three rows, with ten elements in each row. The term 'transition metals' refers only to an element which has PARTIALLY filled d orbitals. Typical example of transition metals include iron (Fe).

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--> Chemical reactivity: In the s- block and p-block, the chemical properties of the elements in the same period vary, often quite markedly, from left to right. This does not happen with the transition metals because electrons are added progressively to the inner d-orbitals.

--> Variable oxidation states: they have variable oxidation states because 3d electrons are available for bond formation.

4 0
4 years ago
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