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4 years ago

How are a flashlight and lightening similar and how are they different?

1 answer:

5 0

A flashlight is an electric-powered light source; the light source is a light bulb or an LED. The electrical energy is converted into visible light. Flashlights can be hand-held or mounted to a platform. Light from a lighting, on the other hand, is formed by exciting electrons to a higher state.

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What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough

olga55 [171]

Answer:

Explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M

6 0

2 years ago

Is this a compound,mixture or solution? (10 points)

goldenfox [79]

Answer:

it is a compound it is a solution when they say they are ablle to seperate it give out they did not mix it

Explanation:

6 0

3 years ago

A ___________ is a heterogeneous mixture in which the particles settle to the bottom.

uysha [10]

<h2>suspension should be correct </h2>

a suspension

the particles are big enough to settle

a colloid

the particles are too small to ever settle

a solution

homogeneous mixture of two or more substances

3 0

3 years ago

A 5.41 g sample of carbon reacts with hydrogen to form 6.32 g of an organic compound. What is the empirical formula of the organ

zhannawk [14.2K]

Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Empirical formula =?

Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Mass of Hydrogen (H) =?

Mass of H = mass of compound – mass of C

Mass of H = 6.32 – 5.41

Mass of H = 0.91 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of C = 5.41 g

Mass of H = 0.91 g

Divide by their molar mass

C = 5.41 / 12 = 0.451

H = 0.91 / 1 = 0.91

Divide by the smallest

C = 0.451 / 0.451 = 1

H = 0.91 / 0.451 = 2

Thus, the empirical formula for the compound is CH₂

3 0

3 years ago

You may want to reference (Page) Section 12.4 while completing this problem. Enter the balanced chemical equation for the comple

alexandr1967 [171]

Answer:

See explanation

Explanation:

In this question, we have to remember that in all combustion reactions we will have Oxygen as reactive ( $O_2$ ) and the products are Carbon dioxide ( $CO_2$ ) and Water ( $H_2O$ ). Additionally, for the states, we will have (l) for the liquid state and (g) for the gas state. So, we can analyze each reaction: