1.73 ÷ 3.7 × 100 = 46.75675675675676
Answer: There is 46.76% of salt in the mixture.
<span>To account for the hexavalency in SF6 one electron each from 3s and 3p orbitals is promoted to 3d orbitals as shown in fig.1.27(b). These six orbitals get hybridised to form six sp3d2hybrid orbitals. Each of these sp3d2 hybrid orbitals overlaps with 2p orbital of fluorine to form S-F bond.
The answer is S(sp3d2)- F(p)</span>
Answer:
<em>The pH of the solution is 7.8</em>
Explanation:
The concentration of the solution is 0.001M and the dye could be in its protonated and deprotonated forms. If the concentration of the protonated form [HA] is 0.0002 M the concentration of the deprotonated form will be the subtraction between the concentration of the bye and the concentration of the protonated form:
[A-] = 0.001M - 0.0002M = 0.0008M
Also, the Henderson-Hasselbalch equation is
this equation shows the dependency between the pH of the solution, the pKa and the concentration of the protonated and deprotonated forms. Thus, replacing in the equation
Polar covalent because it is 2 nonmetals and the molecule has a net dipole movement.
Answer:
6amu
Explanation:
mass=proton+neutron
mass of cl2=2(16+16)=64amu