Answer:
x=3
Step-by-step explanation:
The line of reflection would be at x=3. It’s like a mirror. The reflection is backward, but the same distance from the line of reflection, so the line needs to be halfway between the two shapes. Since C is at 4 and C’ is at 2, the line of reflection has to be at 3.
4×2=8 so n=2 and 8+12=20 so ?=12
Answer: the value for the associated test statistic is 1.2653
Step-by-step explanation:
Given that;
sample size one n₁ = 10
mean one x"₁ = 6.4
standard deviation one S₁ = 1.1
sample size two n₁ = 11
mean two x"₂ = 5.6
standard deviation one S₁ = 1.7
H₀ : μ₁ = μ₂
H₁ : μ₁ ≠ μ₂
Pooled Variance
sp = √( { [(n₁ - 1) × s₁² + (n₂ - 1) × s₂²] / (n₁ + n₂ - 2)} × (1/n₁ + 1/n₂))
we substitute
= √( { [(10 - 1) × (1.1)² + (11 - 1) × (1.7)²] / (10 + 11 - 2)} × (1/10 + 1/11))
= √( { [(9) × 1.21 + (10) × 2.89] / (19) } × (0.1909))
= √({[ 39.79 ] / 19} × (0.1909))
= √( 2.0942 × 0.1909)
= √( 0.39978 )
= 0.63228
Now Test Statistics will be;
t = ( x"₁ - x"₂) / sp
we substitute
t = ( 6.4 - 5.6) / 0.63228
t = 0.8 / 0.63228
t = 1.2653
Therefore the value for the associated test statistic is 1.2653
Answer:
4/9
Step-by-step explanation:
Let the amount of 95% sol = a ml and
the amount of 30% sol = b ml.
So, the total amount of the compound=a+b=500 ml
As the compound is 50% solution, so
95% of a + 30% of b= 50% of (a+b)
(95/100)a+(30/100)b=(50/100)(a+b) [from equation (i)]
95a + 30b = 50(a+b)
95(a/b)+30 = 50(a+b)/b [dividing both sides by b]
95(a/b)+30 = 50(a/b+1)
95(a/b)+30 = 50(a/b)+50
95(a/b)-50(a/b)=50-30
45(a/b)=20
a/b=20/45
a/b=4/9
Therefore, a:b=4:9
As a+b= 500 ml, so the amount of 95% sol = 
ml
and the amount of 95% sol = 
ml
Hence, the proportion of 95% sol and 30% sol to make a compound of 50% sol must be 4/9.
