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Lina20 [59]
3 years ago
12

Can someone please help

Mathematics
1 answer:
scoray [572]3 years ago
8 0
X= # tickets Shaun sold
1/2x+3= # tickets Trudy sold

Add them together.

= x + (1/2x + 3)
combine like terms
= (x + 1/2x) + 3
= 1 1/2x + 3
convert to improper fraction
= 3/2x + 3

ANSWER: 3/2x + 3 (3rd choice down)

Hope this helps! :)
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If y = 12x-2 were changed to y = 12x, how would the graph of the new
Basile [38]

Answer: A. It would be shifted up.

Step-by-step explanation: the only thing that is changing in the two equations is the last number. The last number is not there in the second equation because the y-intercept is 0. The y-intercept in the first equation is -2 and shifts up 2 to y-intercept if 0. Therefore, your answer would be A. It would shift up.

3 0
3 years ago
Find the area of the polygon.
Katen [24]

Answer:

12 x 24 = 288

32 - 24 = 8

8 x 12 = 96

96 divided by 2 = 48

288 + 48 = 336 ft2 is your answer.

6 0
3 years ago
PLEASE PLEASE HELP
marta [7]

Answer:

Approximately 3 grams left.

Step-by-step explanation:

We will utilize the standard form of an exponential function, given by:

f(t)=a(r)^t

In the case of half-life, our rate <em>r</em> will be 1/2. This is because 1/2 or 50% will be left after <em>t </em>half-lives.

Our initial amount <em>a </em>is 185 grams.

So, by substitution, we have:

\displaystyle f(t)=185\big(\frac{1}{2}\big)^t

Where <em>f(t)</em> denotes the amount of grams left after <em>t</em> half-lives.

We want to find the amount left after 6 half-lives. Therefore, <em>t </em>= 6. Then using our function, we acquire:

\displaystyle f(6)=185\big(\frac{1}{2}\big)^6

Evaluate:

\displaystyle f(6)=185\big(\frac{1}{64}\big)\approx2.89\approx 3

So, after six half-lives, there will be approximately 3 grams left.

3 0
3 years ago
What's the median of these numbers:<br> 14,20,24,16,20,18
faltersainse [42]
The answer to this is 19. The reason why is because the median falls between 18 and 20. After that, you have to take the middle number that falls between 18 and 20. In this case, 19. 
4 0
3 years ago
Read 2 more answers
Find the area of the following polygon:
Masja [62]

Given:

ABCD is a quadrilateral

AC = 12, DE = 4 and FB = 5

To find:

The area of the polygon.

Solution:

AC bisects the quadrilateral into two triangles.

Area of triangle:

$A=\frac{1}{2}\times\text{base}\times\text{height}

<u>Area of triangle DAC:</u>

$A=\frac{1}{2}\times AC \times DE

$A=\frac{1}{2}\times 12 \times 4

A=24

Area of triangle DAC = 24 square units.

<u>Area of triangle BAC:</u>

$A=\frac{1}{2}\times AC \times FB

$A=\frac{1}{2}\times 12 \times 5

A=30

Area of triangle BAC = 30 square units.

Area of polygon = Area of triangle DAC + Area of triangle BAC

                           = 24 square units + 30 square units

                           = 54 square units

The area of the polygon is 54 square units.

3 0
3 years ago
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