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Anika [276]
3 years ago
8

Addison earn $25 mowing her neighbor's lawn then she loaned her friend $18 and got 50 from her grandmother for her birthday she

now has $86 how much money did Addison have to begin with
Mathematics
2 answers:
Flura [38]3 years ago
6 0
She had $29. You just do the equation backwards. 86-57=29. 
To check if your answer is correct;
29+25=54
54-18=36
36+50=86
yarga [219]3 years ago
4 0

Solution: The total money did addison have to begin with is $29.

Explanation:

Let the addison begin with money $x.

It is given that the addison earn $25 from his neighbor and $50 from her grandmother. So total money addison has \$x+\$25+\$50=\$x+\$75

She loaned her friend %18.

Now she has \$x+\$75-\$18=\$x+\$57

It is given that she had $86.

\$x+\$57=\$86\\\$x=\$86-\$57\\\$x=\$29

Therefore, the total money did addison have to begin with is $29.

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Mr. Aba builds a circular patio with a diameter of 12 feet. He covers the patio with paving stones. The cost of the paving stone
Anettt [7]

Answer:

395.85

Step-by-step explanation:

If the diameter is 12, then the radius must be 6. Following the formula of pi: 2 * pi * radius, our result is 37.7. 37.7 * 10.50 is 395.85

I really hope this helps. My memory of circles and pi isn't the best.

8 0
2 years ago
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Tye is making trail mix with 3 cups of nuts for every 4 cups of granola. if tye has 6 cups of nuts, how many cups of granola sho
lyudmila [28]
8 cups of granola for 6 cups of nits
8 0
3 years ago
Can someone solve -5x +2y=10
marta [7]

Answer:

x=\frac{2}{5}y-2

Step-by-step explanation:

-5x+2y=10\\-5x+2y-2y=10-2y\\-5x=2y-10\\\frac{-5x}{-5}=\frac{2y-10}{5}\\ x=\frac{2}{5}y-2

6 0
3 years ago
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What is (n+2) / -8=-4
Travka [436]

\frac{n +2}{-8} =-4      Multiply -8 on both sides

\frac{n +2}{-8} (-8)=-4(-8)

n + 2 = 32       Subtract 2 on both sides

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5 0
3 years ago
A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and
gayaneshka [121]

Answer:

(832.156, \ 847.844)

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, \overline x = 840

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

  $E = 7.844$

So, 98% CI is

$(\overline x - E, \overline x + E)$

(840-7.844 ,  \ 840+7.844)

(832.156, \ 847.844)

4 0
3 years ago
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