Answer:
rawr
Step-by-step explanation:
free points
Answer:
(x + 4) × (2x - 5)
Step-by-step explanation:
- Begin by writing 3x as a difference
- 2x^2 + 8x - 5x - 20
- Factor out 2x from the expression
- 2x × (x + 4) - 5x - 20
- Factor out -5 from the expression
- 2x × (x + 4) - 5 (x + 4)
- Factor out x + 4 from the expression
- (x + 4) × (2x - 5)
Hope this helps!!
Lol what I don't understand what u are asking
Answer:
The coordinates of the point that is a reflection of Y(-4, -2) across the x-axis are (
-4,2).
The coordinates of the point that is a reflection of Y across the y-axis are (
4,-2).
Step-by-step explanation:
<em>Reflection across x-axis</em>
<em>The rule used for Reflection across x-axis is that y-coordinate becomes negated while x coordinate remains same.</em>
So,
The coordinates of the point that is a reflection of Y(-4, -2) across the x-axis are (
-4,2).
Because according to definition, x-coordinate remains same, while y-coordinate is negated. So x-coordinate = -4, y-coordinate = 2
<em>Reflection across y-axis</em>
<em>The rule used for Reflection across y-axis is that x-coordinate becomes negated while y coordinate remains same.</em>
So,
The coordinates of the point that is a reflection of Y across the y-axis are (
4,-2).
Because according to definition, y-coordinate remains same, while x-coordinate is negated. So x-coordinate = 4, y-coordinate = -2
Answer:
<u>A. It would be needed 20 packets to transmit 30,000 bytes of information.</u>
<u>B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>
Step-by-step explanation:
1. Let's review the data given to us for solving the question:
Size of each packet of information = 1,500 bytes
Number of packets = P
Number of bytes of information = B
2. Let's answer the questions:
A. How many packets would be needed to transmit 30,000 bytes of information?
P = 30,000 ÷ 1,500
P = 20
<u>It would be needed 20 packets to transmit 30,000 bytes of information</u>
<u>B. </u>How much information could be transmitted in 30,000 packets?
B = 30,000 * 1,500
B = 45'000,000
<u>45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>
