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zloy xaker [14]
3 years ago
11

26 over 35 plus 20 over 25

Mathematics
2 answers:
puteri [66]3 years ago
8 0
\frac{26}{35} +  \frac{20}{25}    →  1\frac{19}{35}
Olenka [21]3 years ago
6 0
26/35 + 20/25
130/175 + 140/175
270/175
54/35
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Iodine-125 has a half-life of about 60 days. How many milligrams of a 500 mg sample will remain after 300 days?
just olya [345]

60 x 5 = 300 days

So five half-lifes = 300 days

Starting amount = 500mg

<span>Amount after 1st half-life = 250 mg</span>

<span>Amount after 2nd half-life = 125 mg</span>

<span>Amount after 3rd half-life = 62.5 mg</span>

<span>Amount after 4th half-life = 31.25 mg</span>

<span>Amount after 5th half-life = 15.625 mg</span>

<span>Hence after 300 days, the amount of iodine-125 will be 15.625 mg out of 500 mg.</span>

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3 years ago
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Travka [436]

Answer:

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Step-by-step explanation:

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So, \Delta ABC\cong \Delta DE F by SAS, if

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5 0
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