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GrogVix [38]
3 years ago
13

What are the domain and range of the function f(x)=-3(x-5)2 +4?

Mathematics
1 answer:
Misha Larkins [42]3 years ago
5 0

Answer:

D=(-infinity, +infinity)

R=(-infinity,  4]

Step-by-step explanation:

I think that 2 is an exponent so you function is f(x)=-3(x-5)^2+4

So if this is the case this is a parabola open down when a vertex of (5,4).

Visualize or draw a rough picture of that because that is all you need to answer this question.

The domain for a parabola function is always all real numbers (do notice I said parabola function).

The range for this parabola is (-infinity, 4]  since open down and the highest point has y value 4.

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posledela

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6 0
4 years ago
Simplify 3 - b (7b + 2) + 3b - (11 - b)​
nirvana33 [79]

Answer: -7b² + 2b - 8

Step-by-step explanation:

<u>Given expression</u>

3 - b (7b + 2) + 3b - (11 - b)

<u>Expand parentheses and apply the distributive property if necessary</u>

=3 - b · 7b - b · 2 + 3b - 11 + b

=3 - 7b² - 2b + 3b - 11 + b

<u>Combine like terms</u>

=-7b² + (3b - 2b + b) + (3 - 11)

=\boxed{-7b^2+2b-8}

Hope this helps!! :)

Please let me know if you have any questions

8 0
3 years ago
Suppose that f(x)=x^2 and g(x)=-1/4(x+7)^2. Which statement best compares the graph of g(x) with the graph of f(x)?
wolverine [178]

Answer:

Both of these graphs are quadratics. They both form a parabola opening up

Step-by-step explanation:

The only difference between g(x) and f(x) is that g(x) is moved to the left 7 unit and has a horizontal stretch of 1/4

5 0
3 years ago
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