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4 years ago

F(x)=x^2=10x+35 what is the value of h when the function is converted to vertex form

2 answers:

8 0

Vertex form is
f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola

f(x)=x^2+10x+35

x^2+10x+25-25+35
x^2+5x+5x+25+10
x(x+5)5(x+5)+10
(x+5)^2+10
where h=-5

puteri [66]4 years ago

7 0

I hope this helps you

y=x^2-10x+35

y=x^2-10x+25+10

y-10=(x-5)^2

y=(x-5)^2+10

h= -(-5)=5

k =10

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3 years ago

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Sonbull [250]

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3 years ago

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3 years ago