All categories

3 years ago

What is the value of m in the figure below? If necessary, round your answer to

Mathematics

1 answer:

Anastasy [175]3 years ago

4 0

<h3>Answer: A) 6.7</h3>

=================================================

Work Shown:

Use the geometric mean formula to find that BD = 6

BD = geometric mean of AD and DC

BD = sqrt(AD*DC)

BD = sqrt(12*3)

BD = 6

Then use the pythagorean theorem to find the missing side for triangle BCD

a^2+b^2 = c^2

(CD)^2 + (BD)^2 = (BC)^2

3^2 + 6^2 = m^2

m^2 = 45

m = sqrt(45)

m = 6.70820393249937 approximately

m = 6.7 after rounding to one decimal place

You might be interested in

I want to know what g is

MAVERICK [17]

Answer:

Step-by-step explanation:

2(5-4g) + 3g - 11 = 5(g-3) - 12 - 3g (remove the parantheses)

10 - 8g + 3g - 11 = 5g - 15 - 12 -3g (Calculate and collect like terms)

-1 - 5g = 2g - 27 (move the terms)

-5g -2g = 27 + 1 (collect like terms and calculate)

-7g = -26 (divide both sides)

so G = 26/7

7 0

3 years ago

Read 2 more answers

Help these are superrrrr hardd

sertanlavr [38]

Answer:

1.) 0

2.) b = -0.8333333333

3.) -x-22

Step-by-step explanation:

Pull out like factors : -3x - 2 = -1 • (3x + 2)

(-5 • (3x + 2) - (x - 3)) - (-16x - 7) = 0

Pull out: -16x-7

After pulling out, we are left with: (-16x-7) • ( 1 +( (-1) ))

Pull out like factors: -16x - 7 = -1 • (16x + 7)

0 = 0

____________________________________________

Simplifying

2(a + -3) + 4b + -2(a + -1b + -3) + 5 = 0

Reorder the terms:

2(-3 + a) + 4b + -2(a + -1b + -3) + 5 = 0

(-3 * 2 + a * 2) + 4b + -2(a + -1b + -3) + 5 = 0

(-6 + 2a) + 4b + -2(a + -1b + -3) + 5 = 0

Reorder the terms:

-6 + 2a + 4b + -2(-3 + a + -1b) + 5 = 0

-6 + 2a + 4b + (-3 * -2 + a * -2 + -1b * -2) + 5 = 0

-6 + 2a + 4b + (6 + -2a + 2b) + 5 = 0

Reorder the terms:

-6 + 6 + 5 + 2a + -2a + 4b + 2b = 0

Combine like terms: -6 + 6 = 0

0 + 5 + 2a + -2a + 4b + 2b = 0

5 + 2a + -2a + 4b + 2b = 0

Combine like terms: 2a + -2a = 0

5 + 0 + 4b + 2b = 0

5 + 4b + 2b = 0

Combine like terms: 4b + 2b = 6b

5 + 6b = 0

Solving

5 + 6b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.

5 + -5 + 6b = 0 + -5

Combine like terms: 5 + -5 = 0

0 + 6b = 0 + -5

6b = 0 + -5

Combine like terms: 0 + -5 = -5

6b = -5

Divide each side by '6'.

b = -0.8333333333

Simplifying

b = -0.8333333333

_______________________________________

|x - 2| - 4*|-6|

=|x - 2| - 4* 6

=|x - 2| - 24

x-2>=0 then x>= 2 and = x-2-24 = x-26

x-2<0 then x<2 and = 2-x-24 =-x-22

so , If x>=2 then the expression will equal x-26

If x<2 then the expression will equal -x-22

_________________________________________

❂✨Answered By Tokyo ✨❂

❉ Brainliest Would Be Appreciated❉

✯If You Have Questions Ask In the Chat Box✯

4 0

3 years ago

SEE ATTACHED FOR QUESTION!!!!!!!!!!! PLS HELP ITS DUE TONIGHT!<br>FIND F(1)

blondinia [14]

Answer:

-6 and -3 for the dots

Step-by-step explanation:

hope this is correct im bad at math

3 0

2 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

3 years ago

12r-5 61°<br> R<br> A) 790<br> C) 140°<br> B) 70°<br> D) 970

Yanka [14]

Answer:

79 because x = 7 so 12 x7 - 5 =79

5 0

2 years ago