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3 years ago

6

What is m∠5? (please view attachment)

2 answers:

lisov135 [29]3 years ago

7 0

Angle 5 is identical to Angle 2

so it would be 27 degrees

Fofino [41]3 years ago

5 0

27 degrees is the answer
:)

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The local skating rink pays Mary a fixed rate per pupil plus a base amount to work as a skating instructor. She earns $90 for in

liq [111]

The expressions for the payment made to Mary are,
(Monday) 90 = 15m + b
(Tuesday) 62 = 8m + b
where m and b are the fee per student and the base fee, respectively. Solving for m and b, the values are 4 and 30.
The equation that represents Mary's earning is
y = 4x + 30
For 20 students,
y = 4(20) + 30 = 110
For Lisa's earnings,
y = 8x + 15
Substituting 20,
y =8(20) + 15 = 175
Thus, Lisa would earn more than Mary by $65.

6 0

4 years ago

Consider the following equations:

Veseljchak [2.6K]

Answer:

c number is the correct one i think

6 0

3 years ago

Read 2 more answers

What is f(3) if f(x) = 2x + 1?

Vlad [161]

Answer:f= 2/3x+1/3

Step-by-step explanation:

divide both sides by 3 to get the answer

7 0

3 years ago

The function N(t) = 100e^−0.023t models the number of grams in a sample of cesium-137 that remain after t years. On which interv

Andreas93 [3]

Options:

A. [1,10] B. [10,20] C. [15,25] D. [1,30]

Answer:

A. [1,10]

Step-by-step explanation:

Given

$N(t) = 100e^{-0.023t}$

Required

Interval with the fastest rate of decay

The rate of change over [a,b] is calculated as:

$Rate = \frac{N(b) - N(a)}{b - a}$

So, we have:

A. [1,10]

$Rate = \frac{N(10)-N(1)}{10 - 1}$

$Rate = \frac{N(10)-N(1)}{9}$

Calculate N(10) and N(1)

$N(10) = 100e^{-0.023*10} = 100e^{-0.23} = 79.45$

$N(1) = 100e^{-0.023*1} = 100e^{-0.023} = 97.73$

So:

$Rate = \frac{79.45-97.73}{9} = \frac{-18.28}{9} = -2.03$

B. [10,20]

$Rate = \frac{N(20)-N(10)}{20 - 10}$

$Rate = \frac{N(20)-N(10)}{10}$

Calculate N(20) and N(10)

$N(20) = 100e^{-0.023*20} = 100e^{-0.46} = 63.13$

$N(10) = 100e^{-0.023*10} = 100e^{-0.23} = 79.45$

So:

$Rate = \frac{63.13 - 79.45}{10} = \frac{-16.32}{10} = -1.632$

C. [15,25]

$Rate = \frac{N(25)-N(15)}{25 - 15}$

$Rate = \frac{N(25)-N(15)}{20}$

Calculate N(25) and N(15)

$N(25) = 100e^{-0.023*25} = 100e^{-0.575} = 56.27$

$N(15) = 100e^{-0.023*15} = 100e^{-0.345} = 70.82$

So:

$Rate = \frac{56.27 - 70.82}{10} = \frac{-14.55}{10} = -1.455$

D. [1,30]

$Rate = \frac{N(30)-N(1)}{30 - 1}$

$Rate = \frac{N(30)-N(1)}{29}$

Calculate N(30) and N(1)

$N(30) = 100e^{-0.023*30} = 100e^{-0.69} = 50.16$

$N(1) = 100e^{-0.023*1} = 100e^{-0.023} = 97.73$

So:

$Rate = \frac{50.16 - 97.73}{29} = \frac{-47.57}{29} = -1.64$

By comparing the values of the calculated rates,

-2.03 is the smallest, in other words; the fastest rate

Hence, the interval [1,10] has the fastest rate of decay

4 0

3 years ago

krystina needs 9 in of string to make a bracelet.if she has 16 ft of string,what is the maximum number of bracelets that she can

maw [93]

Answer:

16*12(inches in a foot)=

192 inches in 16 feet

then we divide by 9

192/9=

21.3333333333

so she can make 21

Hope This Helps!!!

7 0

3 years ago

Read 2 more answers