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3 years ago

6

What is m∠5? (please view attachment)

2 answers:

lisov135 [29]3 years ago

7 0

Angle 5 is identical to Angle 2

so it would be 27 degrees

Fofino [41]3 years ago

5 0

27 degrees is the answer
:)

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You are shipping a box that weighs 5 pounds. Shipping charges are listed by ounces at the local mail center. The first ounce cos

tatyana61 [14]

Answer:

C

Step-by-step explanation:

First you must know that there are 16 ounces in 1 pound so the amount of ounces in 5 pounds would be 80 ounces so first you would take out one ounce for the $0.35 and would then have 79 ounces. After that you would multiply 79 by .10 to get 7.90 then add the .35 to that to get

8.25. So the answer is c.

8 0

3 years ago

Read 2 more answers

The area of a trapezoid is 70.55 square feet. The length of the bases are 11.4 and 5.6 feet. What is the height of the trapezoid

olasank [31]

Answer:

The height is 8.3 feet

Step-by-step explanation:

The area of a trapezoid is calculated using the formula:

Area=½(sum of bases)*height

We substitute area=70.55, and the base lengths 11.4 and 5.6 feet and solve for the height.

$70.55 = \frac{1}{2} (11.4 + 5.6)h$

$70.55 = \frac{1}{2} (17)h$

$70 .55 = 8.5h$

$h = \frac{70.55}{8.5}$

$h = 8.3$

5 0

3 years ago

Read 2 more answers

Volume = 154 cm cubic

zheka24 [161]

Cylinder Volume

Level : JHS

V = hπr²

154 cm³ = 16 cm × 3.14 × r²

154 cm³ = 50.28 cm × r²

r² = 154 cm³ : 50.28 cm

r² = 3.0625 cm²

r = 1.75 cm

d = 2r

d = 2 × 1.75 cm

d = 3.5 cm

So, the diameter of the Cylinder is 3.5 cm

#LearnWithEXO

8 0

3 years ago

Write fraction or mixed number as decimal 27/75

jarptica [38.1K]

9/3. 5/14 hope that's the right awnser

5 0

3 years ago

Read 2 more answers

Find the coordinates of the circumcenter for ∆DEF with coordinates D(1,3) E (8,3) and F(1,-5). Show your work.

luda_lava [24]

Answer: The coordinates of the circumcenter is $(\frac{9}{2}, -1)$ .

Explanation:

The coordinates of triangle DEF are D(1,3) E (8,3) and F(1,-5).

Distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$DE=\sqrt{(8-1)^2+(3-3)^2}=7$

$FE=\sqrt{(1-8)^2+(-5-3)^2}=\sqrt{7^2+8^2}$

$DF=\sqrt{(1-1)^2+(-5-3)^2}=8$

Since triangle follows pythagoras theorem,

$(DF)^2+(DE)^2=(FE)^2$

Therefore the given triangle is a right angle triangle.

Or plot these points on a coordinate plane. From the figure we can say that the triangle DEF is a right angle triangle.

The circumcenter of a right angle triangle is the midpoint of the hypotenuse.

The hypotenuse is EF. The midpoint of EF is,

$Midpoint =(\frac{8+1}{2}, \frac{3-5}{2} )=(\frac{9}{2}, -1)$

Therefore, the coordinates of the circumcenter is $(\frac{9}{2}, -1)$ .

5 0

3 years ago