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3 years ago

Subtract the quotient of 18 and 3 from the sum of 22 and 9

Mathematics

2 answers:

netineya [11]3 years ago

7 0

25 cuz 18/3=6 and 22+9=31. 31-6=25

ExtremeBDS [4]3 years ago

4 0

18/3=6 and 22+9=31 so 31-6=25

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What is the value of the expression <br> (-1.25)(.5)(4)

sammy [17]

Answer:

2.5

Step-by-step explanation:

3 0

3 years ago

One apple and three oranges cost $5.10 and another 5 oranges and one Apple cost $7.50 what is the price of one apple and one ora

alekssr [168]

Answer:

$2.7

Step-by-step explanation:

Let the price of one apple be x

and the price of one orange y

Hence ;

One apple and 3 oranges would cost:

x + 3×y = $5.10----------------------------(1)

One apple and 5 oranges would cost;

x + 5×y = $7.50--------------------------(2)

Subtracting eqn (1) from (2), we have :

x-x + 5y -3y = 7.5- 5.1

2y = 2.4

y = $1.2

From eqn(1)

x + 3y = $5.10

x= $5.10-3($1.2) = $5.10-$3.6 = $1.5

Hence x=$1.5 and y= $1.2

We are required to find the cost of one apple and one orange, hence :

x+y = $1.5+$1.2= $2.7

4 0

3 years ago

Cindy has $25 saved and earns $12 per week for walking dogs. Mindy has $55 saved and earns $7 per week for watering plants. Cind

Rufina [12.5K]

Answer:

c : they will have both saved 97

Step-by-step explanation:

7*6 = 42 + 55(base) = 97

12*6 = 71 = 25(base) =97

7 0

2 years ago

A triangle with side lengths of 32, 60 and 68 is a right triangle?<br> true or false

Troyanec [42]

I believe that it would come out to become true

5 0

4 years ago

Read 2 more answers

A model rocket is launched with an initial velocity of 200 ft per second. The height h, in feet, of the rocket t seconds after t

Solnce55 [7]

Answer:

2.10 s, 10.40 s.

Step-by-step explanation:

We know that the height of the rocket is given by the function:

$h=-16t^2+200t$

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

$350=-16t^2+200t$

The last is a quadratic equation, which can be put in the form $at^2+bt+c=0$ and solved applying the formula:

$t=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

So, let's put the equation on the form $at^2+bt+c=0$ adding $16t^2$ and subtracting $200t$ to each side of the equation; the result is:

$16t^2-200t+350=0$

So, we note that a=16, b=-200, and c=350.

Then,

$t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10$

$t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40$

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

4 0

3 years ago