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Anettt [7]
3 years ago
10

The probability that a normal random variable is less than its mean is ____. ​​1.0 ​0.5 ​0.0 ​Cannot be determined?

Mathematics
1 answer:
Ber [7]3 years ago
7 0
The correct answer for the question that is being presented above is this one: "​0.5" <span>The probability that a normal random variable is less than its mean is 0.5. In a normal distribution, 1.0 refers to the one that is stable and is in equilibrium.</span>
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Please help as soon as possible
MAVERICK [17]

Answer: Your Answer is: -8/17

7 0
3 years ago
Please help due ASAP <br> I really need help
elena55 [62]
C because it is icoceles.
6 0
3 years ago
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Let A, B, C and D be sets. Prove that A \ B and C \ D are disjoint if and only if A ∩ C ⊆ B ∪ D
ANEK [815]

Step-by-step explanation:

We have to prove both implications of the affirmation.

1) Let's assume that A \ B and C \ D are disjoint, we have to prove that A ∩ C ⊆ B ∪ D.

We'll prove it by reducing to absurd.

Let's suppose that A ∩ C ⊄ B ∪ D. That means that there is an element x that belongs to A ∩ C but not to B ∪ D.

As x belongs to A ∩ C, x ∈ A and x ∈ C.

As x doesn't belong to B ∪ D, x ∉ B and x ∉ D.

With this, we can say that x ∈ A \ B and x ∈ C \ D.

Therefore, x ∈ (A \ B) ∩ (C \ D), absurd!

It's absurd because we were assuming that A \ B and C \ D were disjoint, therefore their intersection must be empty.

The absurd came from assuming that A ∩ C ⊄ B ∪ D.

That proves that A ∩ C ⊆ B ∪ D.

2) Let's assume that A ∩ C ⊆ B ∪ D, we have to prove that A \ B and C \ D are disjoint (i.e.  A \ B ∩ C \ D is empty)

We'll prove it again by reducing to absurd.

Let's suppose that  A \ B ∩ C \ D is not empty. That means there is an element x that belongs to  A \ B ∩ C \ D. Therefore, x ∈ A \ B and x ∈ C \ D.

As x ∈ A \ B, x belongs to A but x doesn't belong to B.  

As x ∈ C \ D, x belongs to C but x doesn't belong to D.

With this, we can say that x ∈ A ∩ C and x ∉ B ∪ D.

So, there is an element that belongs to A ∩ C but not to B∪D, absurd!

It's absurd because we were assuming that A ∩ C ⊆ B ∪ D, therefore every element of A ∩ C must belong to B ∪ D.

The absurd came from assuming that A \ B ∩ C \ D is not empty.

That proves that A \ B ∩ C \ D is empty, i.e. A \ B and C \ D are disjoint.

7 0
3 years ago
Solve for x:<br>7x(x+1.8)=0<br><br>Need help ASAP.
andrew11 [14]

Answer:

i got you

Step-by-step explanation:

for x1= -1.8 and x2=0

3 0
2 years ago
Read 2 more answers
Plz help ASAP I will mark u branliest
-BARSIC- [3]

Answer:

Brainliest?

Step-by-step explanation:

1.

subtract 1 from both sides

divide by 2

2.

add 5 to each side

divide by 4

6 0
2 years ago
Read 2 more answers
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